4. In a significance test, you calculate a P-value of 0.0358. A correct interpretation of this P-value would be: a. About 3.6% of the data are significant b. About 3.6% of all the samples are significant C. About 3.6% of all samples would produce a test statistic at least as extreme as ours if the null. hypothesis is true. D d. There is sufficient evidence to reject the null hypothesis e. There is not sufficient evident to reject the null hypothesis

4. In a significance test, you calculate a P-value of 0.0358. A correct interpretation of this P-value would be: a. About 3.6% of the data are significant b. About 3.6% of all the samples are significant C. About 3.6% of all samples would produce a test statistic at least as extreme as ours if the null. hypothesis is true. D d. There is sufficient evidence to reject the null hypothesis e. There is not sufficient evident to reject the null hypothesis

Name: 4. In a significance test, you calculate a P-value of 0.0358. A corre
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Description: 4. In a significance test, you calculate a P-value of 0.0358. A correct interpretation of this P-valuewould be:a. About 3.6% of the data are significantb. About 3.6% of all the samples are significantC. About 3.6% of all samples would produce a test

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? The test statistic, t, The P-value is State the conclusion for the test. A. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. B. Reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. D. Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that…
A. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative and hypotheses? B. What is the test statistic? (Round to two decimal places as needed.) C. What is the P-value? (Round to three decimal places as needed.) State the conclusion for the test. A. Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.B. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.D. Reject the null hypothesis. There is not sufficient evidence to support…
You wish to test the following claim (Ha) at a significance level of a = 0.01. H.: u = 78.5 H.:u < 78.5 You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: data 64.5 63.5 72.4 68.2 58.3 65 What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a
A statement of “no difference” that contradicts the research hypothesis and is always expressed in terms of population parameters is called the a. null hypothesis. b. right-tailed test. c. t statistic. d. specified value
courses/50306/assignments/608635?module_item_id=1106150 You wish to test the following claim (Ha) at a significance level of a = 0.005. H.:µ = 59.4 Ha:u < 59.4 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n = 24 with mean M = 51.1 and a standard deviation of SD = 9.7. What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This p-value leads to a decision to... O reject the null O accept the null O fail to reject the null As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the claim that the population mean is less than 59.4. O There is not sufficient evidence to warrant rejection of the claim that the population mean is less than 59.4. O The sample data support the claim that the population mean is less than 59.4. OThere i not sufficient sample ovidence to…
A poll of 2,122 randomly selected adults showed that 93% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p = 0.92 vs p *0.92 Sample X 1 N 2,122 1970 Sample p 0.928369 95% CI The P-value is (Round to three decimal places as needed.) (0.917397,0.939341) a. Is the test two-tailed, left-tailed, or right-tailed? O Two-tailed test O Left-tailed test O Right tailed test b. What is the test statistic? The test statistic is (Round to two decimal places as needed.) c. What is the P-value? Z-Value 1.42 P-Value 0.155
Answer the given problem below by following in hypothesis testing. Sample problem: Determine the weight of the students before and during the quarantine. Did the students lose more fat before the quarantine? Weight before quarantine: sample mean = 5.9 kg sample standard deviation = 4.1 kg sample size = n = 42 standard error = SEM1 = 4.1/ √42 = 0.633 Weight during quarantine: sample mean = 4.1 kg sample standard deviation = 3.7 kg sample size = n = 47 standard error = SEM2 = 3.7/ √47 = 0.540 measure of variability = sq root [(0.633)2 + (0.540)2] = 0.83 1. Determine the p-value = 0.03 (LOS= 95%; α=0.05) 2. Make a decision 3. Conclusion
2. Which one of the following statements is correct? A. If you are told a sample percentage is 25%, you would need to know the sample size in order to convert that percentage to a proportion. B. We always begin a hypothesis test by assuming that the alternative hypothesis is true. C. The test statistic is affected by the size of the sample. D. A small P-value means we have evidence in favor of the null hypothesis. E. The test statistic will be negative if the claimed population proportion is smaller than the sample proportion.
Consider testing the hypotheses Ho: p 0.4 versus Hai p> 0.4. Four possible sample statistics, along with four possible p-values, are given. Match the statistics to their p-values. p= 0.42 p=0.38 p= 0.51 p= 0.46 D
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a. if the null hypothesis is true (avg. anxiety level score of children in the sample is the same as the avg. nationwide score; mu = 100), what can you say about the distribution of x-bar among simple random samples of 46 children? b. calculate the p-value on this distribution. given the p-value, what conclusions can you draw?
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