4. In a significance test, you calculate a P-value of 0.0358. A correct interpretation of this P-value would be: a. About 3.6% of the data are significant b. About 3.6% of all the samples are significant C. About 3.6% of all samples would produce a test statistic at least as extreme as ours if the null. hypothesis is true. D d. There is sufficient evidence to reject the null hypothesis e. There is not sufficient evident to reject the null hypothesis

4. In a significance test, you calculate a P-value of 0.0358. A correct interpretation of this P-value would be: a. About 3.6% of the data are significant b. About 3.6% of all the samples are significant C. About 3.6% of all samples would produce a test statistic at least as extreme as ours if the null. hypothesis is true. D d. There is sufficient evidence to reject the null hypothesis e. There is not sufficient evident to reject the null hypothesis

Name: 4. In a significance test, you calculate a P-value of 0.0358. A corre
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Description: 4. In a significance test, you calculate a P-value of 0.0358. A correct interpretation of this P-valuewould be:a. About 3.6% of the data are significantb. About 3.6% of all the samples are significantC. About 3.6% of all samples would produce a test

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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11. Add 6 to each number in the dataset. Then, the 15th percentile is:a. 1b. 6c. 8d. 7Use the following information to answer questions 12-14: Suppose the probability that an adult gets thenews from Facebook is 0.60. A random sample of 14 adults were surveyed to determine X, the numberof adults who get their news from Facebook.12. Which of the following statements is false?a. The set of possible x-values is {1, 2, 3, . . ., 14}b. X ~ B (14, 0.60)c. P(X=5) = 0.0408d. µ = 8.413. Find the probability that at least 6 adults get their news from Facebook.a. 0.8499b. 6/14c. 0.6429d. 0.941714. X is of data of type:a. categorical nominalb. categorical ordinalc. numerical continuousd. numerical discrete15. Suppose that the ages of Brunswick CC students are normally distributed. A random sample of 6Brunswick CC students reported the ages of 20, 35, 18, 45, 27, and 20 years old. Find the errorbound that corresponds to the 90% confidence interval for the true population mean age ofBrunswick CC…
Answer the given problem below by following in hypothesis testing. Sample problem: Determine the weight of the students before and during the quarantine. Did the students lose more fat before the quarantine? Weight before quarantine: sample mean = 5.9 kg sample standard deviation = 4.1 kg sample size = n = 42 standard error = SEM1 = 4.1/ √42 = 0.633 Weight during quarantine: sample mean = 4.1 kg sample standard deviation = 3.7 kg sample size = n = 47 standard error = SEM2 = 3.7/ √47 = 0.540 measure of variability = sq root [(0.633)2 + (0.540)2] = 0.83 1. Determine the p-value = 0.03 (LOS= 95%; α=0.05) 2. Make a decision 3. Conclusion
In each part, we have given the value obtained for the test statistic, z, in a one-mean z-test.We have also specified whether the test is two tailed, left tailed, or right tailed. Determine the P-value in each case and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. a. z = -1.25; left-tailed testb. z = 2.36; right-tailed testc. z = 1.83; two-tailed test
please answer d, e, f f; accept, reject, fail to reject
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Consider testing the hypotheses Ho: p 0.4 versus Hai p> 0.4. Four possible sample statistics, along with four possible p-values, are given. Match the statistics to their p-values. p= 0.42 p=0.38 p= 0.51 p= 0.46 D
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a. if the null hypothesis is true (avg. anxiety level score of children in the sample is the same as the avg. nationwide score; mu = 100), what can you say about the distribution of x-bar among simple random samples of 46 children? b. calculate the p-value on this distribution. given the p-value, what conclusions can you draw?
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