4. In a compound generator connected short-shunt, the induced emf in the armature is 236.4 voltswhen it delivers 150 amperes to the load. The shunt field current is 2.5 A and the armatureresistance is 0.032 2. The series field resistance is 0.015 N and is being shunted with a diverterof resistance Ra. At this condition the electrical efficiency is 95.697%. Determine terminalvoltage, diverter resistance Ra and electrical losses.(a) 230V, 0.031N & 1,550.45W(b) 232V, 0.031Q & 2,550.68W(c) 230V, 0.074N & 1,674.52W(d) 230V, 0.031Q & 1,850.42W

Given Short shunt compound generator Induced EMF in the armature E=236.4 vLoad current IL=150 AThe…

4. In a compound generator connected short-shunt, the induced emf in the armature is 236.4 volts when it delivers 150 amperes to the load. The shunt field current is 2.5 A and the armature resistance is 0.032 2. The series field resistance is 0.015 2 and is being shunted with a diverter of resistance R4. At this condition the electrical efficiency is 95.697%. Determine terminal voltage, diverter resistance Ra and electrical losses. (a) 230V, 0.031Q & 1,550.45W (b) 232V, 0.031N & 2,550.68W (c) 230V, 0.0742 & 1,674.52w (d) 230V, 0.031Q & 1,850.42W

4. In a compound generator connected short-shunt, the induced emf in the armature is 236.4 volts when it delivers 150 amperes to the load. The shunt field current is 2.5 A and the armature resistance is 0.032 2. The series field resistance is 0.015 2 and is being shunted with a diverter of resistance R4. At this condition the electrical efficiency is 95.697%. Determine terminal voltage, diverter resistance Ra and electrical losses. (a) 230V, 0.031Q & 1,550.45W (b) 232V, 0.031N & 2,550.68W (c) 230V, 0.0742 & 1,674.52w (d) 230V, 0.031Q & 1,850.42W

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Winding and Constructions

Alternating Current (AC) winding is generally of the 3-phase type due to the inherent advantages of the 3-phase machine. Armature coils must be connected to the yield balance (equivalent in magnitude and 2/3 of the series phase difference of the rod) 3-phase electromotive forces (emf). The armature should be divided into step-bands to start with slots around the perimeter.In the construction of AC machines, the frame is used as an external protective shield to protect it from environmental conditions. The frame also serves as the outer perimeter, allowing the interior to be easily placed. The static state section of the devices is the stator winding attached stator.

Question

4. In a compound generator connected short-shunt, the induced emf in the armature is 236.4 volts
when it delivers 150 amperes to the load. The shunt field current is 2.5 A and the armature
resistance is 0.032 2. The series field resistance is 0.015 N and is being shunted with a diverter
of resistance Ra. At this condition the electrical efficiency is 95.697%. Determine terminal
voltage, diverter resistance Ra and electrical losses.
(a) 230V, 0.031N & 1,550.45W
(b) 232V, 0.031Q & 2,550.68W
(c) 230V, 0.074N & 1,674.52W
(d) 230V, 0.031Q & 1,850.42W

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The series field winding of a 170 kW, 250 V, 1450 rpm compound generator has a resistance of 0.00306 ohm. What will be the required resistance (in Ohm) of a noninductive diverter that will bypass 27 percent of the total armature current? "
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(a) A 6 pole generator with lap wound armature has 135 slots each having 14 conductors. The flux per pole is 20 mWb. At what speed must the armature rotate to give an induced EMF of 210V. (b) What will be the voltage developed, if the winding is wave connected and the armature rotates at the same speed
9.09 The flux density distribution in the air-gap of a certain generator is such that it contains a fundamental, a third harmonic, and a fifth harmonic. The flux per pole due to the fundamental distribution is 9 x 10-3 weber, that due to the third harmonic distribution is 0.9 x 10-3 weber, that due to the fifth harmonic distribution is 0.4 x 103 weber. There are four armature slots per phase per pole, the connection are made for three-phase wye. and the coil pitch is 12/15. The frequency is 60 cycles and the generator has 4 poles. (a) Calculate the emf/turn. (b) If there are six turns/coil and two coil sides/slot, calculate the emf per phase. (c) Calculate the emf between line terminals. Ans. 2.32V; 212V; 364V
The armature reaction occurs when a separately excited generator supplies rated load: Is always present Is always absent May be sometimes present None of the above
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D2. When a generator's full-load output voltage is the same as its no-load output voltage it is said to be a) under-compounded b) flat-compounded c) over-compounded d) none of the above D3. The output of an overcompounded DC generator can be lowered by use of a a) rheostat connected in series with the series field b) rheostat connected in parallel with the series field c) rheostat connected in parallel with the shunt field d) none of the above D4. When might it be desirable to use an overcompounded generator? a) never b) always c) to compensate for line loss d) when you need a higher no-load voltage than your full-load voltage