4. (I) What is the repulsive electrical force between two protons 4.0 × 10-¹5 m apart from each other in an atomic nucleus?
4. (I) What is the repulsive electrical force between two protons 4.0 × 10-¹5 m apart from each other in an atomic nucleus?
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![### Question 4
#### (1) What is the repulsive electrical force between two protons 4.0 x 10⁻¹⁵ m apart from each other in an atomic nucleus?
**Details to Include:**
- **Protons:** The positively charged particles found within atomic nuclei.
- **Distance:** The distance given between the two protons is 4.0 x 10⁻¹⁵ meters.
- **Concept:** The focus is on calculating the electrical (or electrostatic) force between the two protons due to their charge.
**Relevance in Physics:**
This question deals with concepts from electrostatics, specifically the Coulomb's Law, which is used to calculate the force between two charged particles. Coulomb's Law states that the force (F) between two charges (q₁ and q₂) is directly proportional to the product of the charges and inversely proportional to the square of the distance (r) between them.
### Formula
\[ F = k_e \frac{|q_1 q_2|}{r^2} \]
Where:
- \( F \) is the magnitude of the force between the charges,
- \( k_e \) is Coulomb's constant (\( 8.988 \times 10^9 \, \text{N m}^2/\text{C}^2 \)),
- \( q_1 \) and \( q_2 \) are the amounts of the two charges (For protons, \( q = 1.602 \times 10^{-19} \, \text{C} \)),
- \( r \) is the distance between the charges (4.0 x 10⁻¹⁵ m in this case).
Using the formula above, students can calculate the repulsive force between the protons.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcaea1532-9bca-456b-84fc-9594bcc8dc11%2F04834d1f-b0c6-447d-8eb7-dc201b37f571%2Fe771nig_processed.png&w=3840&q=75)
Transcribed Image Text:### Question 4
#### (1) What is the repulsive electrical force between two protons 4.0 x 10⁻¹⁵ m apart from each other in an atomic nucleus?
**Details to Include:**
- **Protons:** The positively charged particles found within atomic nuclei.
- **Distance:** The distance given between the two protons is 4.0 x 10⁻¹⁵ meters.
- **Concept:** The focus is on calculating the electrical (or electrostatic) force between the two protons due to their charge.
**Relevance in Physics:**
This question deals with concepts from electrostatics, specifically the Coulomb's Law, which is used to calculate the force between two charged particles. Coulomb's Law states that the force (F) between two charges (q₁ and q₂) is directly proportional to the product of the charges and inversely proportional to the square of the distance (r) between them.
### Formula
\[ F = k_e \frac{|q_1 q_2|}{r^2} \]
Where:
- \( F \) is the magnitude of the force between the charges,
- \( k_e \) is Coulomb's constant (\( 8.988 \times 10^9 \, \text{N m}^2/\text{C}^2 \)),
- \( q_1 \) and \( q_2 \) are the amounts of the two charges (For protons, \( q = 1.602 \times 10^{-19} \, \text{C} \)),
- \( r \) is the distance between the charges (4.0 x 10⁻¹⁵ m in this case).
Using the formula above, students can calculate the repulsive force between the protons.
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