2022.04.22 21:44Activity 2.1: Find My Value!Directions: Determine the test statistic used then find its value basedon the given information. Express your answer to the nearestthousandths. Show your solutions.sampleon is 8.5, and the sample size is 20. Use a2. HSamplese a = 0.01.34. Ho: μ = 8.3Ha: μ# 8.3The sample mean is 9.2 and the sample size is 50. The population follows anormal distribution with standard deviation 3.10. Use a = 0.05.5. Ho: μ = 170Ha: μ> 170The population is approximately normal. The sample mean is 176, the samplestandard deviation is 13.5, and the sample size is 25. Use a = 0.01.The peActis haSOF

Given that Sample size n =50 Sample mean =9.2 Population standard deviation =3.10 NOTE:- According…

Answered: 4. Ho: μ = 8.3 Ha: 8.3 The sample mean…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Find the proportion of Normally distributed observations with a z-score above 0.80. Give your answer to four decimal places. Find the proportion of N.d. observations with a z-score between z1= -0.34 and z2= 2.72. Give your answer to four decimal places.
Need help with this one in part D.
Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…
The distribution of heights in a population of women is approximately normal. Sixteen percent of the women have heights less than 62 inches. About 97.5% of the women have heights less than 71 inches. Use the empirical rule to estimate the mean and standard deviation of the heights in this population. Mean: K inches Standard Deviation: inches
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This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.
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Draw the normal curve using the data given b. x = 83. s = 6 a.x = 30. s = 8 %3D

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4. Ho: μ = 8.3 Ha: 8.3 The sample mean is 9.2 and the sample size is 50. The population follows a normal distribution with standard deviation 3.10. Use a = 0.05.