4. For each of the following molecular formulae, how many elements of unsaturation are present? C10H22O2 C₂HCISO₂ C7H7Br₂NO2 C16H10 (Draw a reasonable organic molecule with this formula) CastHasFINP115e30sa ⚫ CH2 (What might the structure of this species be? How can it have a nonzero number of elements of unsaturation without any rings or pi bonds?) • C₂H9B (Oh dear! I never told you what to do with boron...)

4. For each of the following molecular formulae, how many elements of unsaturation are present? C10H22O2 C₂HCISO₂ C7H7Br₂NO2 C16H10 (Draw a reasonable organic molecule with this formula) CastHasFINP115e30sa ⚫ CH2 (What might the structure of this species be? How can it have a nonzero number of elements of unsaturation without any rings or pi bonds?) • C₂H9B (Oh dear! I never told you what to do with boron...)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Please check if information below about alcohols and ethers in organic chemistry are correct please I am really having troubl ALCOHOLS AND ETHERS INTRODUCTION: Alcohols: Organic compounds with (-OH) groups attached to a carbon atom Used as solvents, fuels, and in the production of chemicals/pharmaceuticals Have biological roles and are found in alcoholic beverages Alcohols have a characteristic -OH group, which gives them a polar nature and makes them soluble in water and other polar solvents. They have higher boiling points compared to similar-sized hydrocarbons due to the hydrogen bonding between the -OH groups. Alcohols can undergo oxidation reactions to form aldehydes, ketones, and carboxylic acids. They can also undergo dehydration reactions to form alkenes and water. Ethers: Organic compounds with an oxygen atom bonded to two carbon atoms Ethers have a relatively non-polar nature due to the lack of a polar -OH group. As a result, they have low solubility in water…
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Can you please answer the question #2? Thanks