4. Find the value of all the resistors in the circuit of Figure 4 and calculate the total power dissipated in them. 2A w R3 W R₁ 1A R2 RA w ww 1A 1A 10 V + 15 V + 5A 20 V R5 Figure 4: Circuit for problem 4
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- 4.-For-labeled currents, draw an arrow to show the direction of the actual positive current. For labeled voltages, circle the node that is at the actual highest potential. Note that the positive and negative signs of the voltage represent the polarity of the probes of a voltmeter connected to the device. The value shown is the reading on the voltmeter. (segment of wire) 2A -2A -5A 2.de 3A TA Cov E 5V 12V + 3V -10V -2017. The equivalent total resistance in the circuit in Figure 1 is_ 2200 E=7V- 1000. 4700. 100. 3300 Figure 1 1. 558.90 2. 2160 3. 642.450 4. 82.892 8. The current through the 1002 resistor in the circuit in Figure 1 is_ 1. 84.45mA 2. 70mA 3. 14.89mA 4. 17.51mA 9. The power dissipated by the 3302 resistor in the circuit in Figure 1 isPlease answer in typing format
- The figure shows a circuit. The switch S can be closed on either point A or C, but not both at the same time. Use the following quantities: V₁ = V₂ = 12 V R₁ = R4 = 1.00 R₂ = R3 = 2.00 [ R 4 O 2A O 6 A O 1 A O 12 A S О ЗА R₁ Determine the current through R₁ when the switch S is closed on A. W K Bm! BThe figure is shown a circuit consisting of a resistor Rị in series with two resistors R2 and R3 in parallel. The circuit is connected across a constant 100 V supply. When switch S is open, the ammeter A, reads 8 amperes. When switch S is closed A1 reads 10 amperes and A2 reads 4 A. determine (a) ohms of resistors R1, R2 and R3. (b) Voltage across R,& R2 when S is open. (c) Voltage across R1 & R2 when S is closed. R1 {A1 -v A2 S1 100V R2 R32 / 5 100% P Name: AENT 3823 Series, Parallel, and Combination Resistive Circuits Exam 01. Determine/Calculate the values for the missing variables. Show your work. Given values are in italics. (13 Pts) R2 = 500 V₁ = 30V R1 = 1000 What type of circuit is this? VT= 30 V Vi= V₂- V V₁ = V5- Q Search hp 144 Dl DAI W R3 = 250 R5 = 2502 w R4 = 2500 M R+= R= 1000 R₂ R2=500 Rs 250 13 = R₁ = Rs 2500 14= 25 Is= delete home 12. insert prt sc
- Determine the current of the circuit below. Then apply Ohm's law to determine the expected voltage drops across R1, R2, and R3. Record these values. Include demonstration of Kirchhoff's Voltage Law. R1 1k 9Vdc R2 220 R3 10kThe figure below shows the resistors wired in a different way-a combination of series and parallel. We can consider R₁, to be the resistance of wires leading to R₂ and R³ a. Find the total resistance. b. What is the IR drop in R₁? c. Find the current I through R₂. d. What power is dissipated by R₂?Give me right solution with clear calculations
- The emfs in the figure below are ₁ = 5.00 V and ₂ = 18.0 V. The resistances are R₁ = 17.00, R₂ = 31.00, R3 = 47.002, and R4 = 57.0 Q. Find the magnitude of the current in each resistor when the switch is in the following states. R₂ (a) open I₁ = DI I2 = 13 = I4 = (b) closed I₁ = 12 = R4 13 = I4 = A A A A A A A A S R₁ mw R₂ E₂Circle. For the circuit shown below, find I1, 12, 13: 1 2. Voltage across each resistor. 3. Disconnect the sources of voltage. Rtotal and select *We now have a function file called myCircuit.m that solves for the currents in the following system of equations: i₁ + 12 = 13 V₁-i₁R₁ - 13R3 = 0 V2-i2R2 - 13R3 = 0 The circuit has R₁ = 1022, R₂ = 2002, and R3 = 409. The first battery has a fixed voltage V₁ = 35V, but the second battery can be adjusted to anything between 20V and 60V. We want the current is to be 0.77A. We will find the V₂ that produces this current by starting at V₂ = 20V and incrementing V₂ by 0.01V until we get i3 greater than or equal to 0.77A. Write a script file called current.m that calls myCircuit.m inside a while loop in order to determine what voltage we should select for V₂. This problem assesses how you can handle vector outputs to functions.