1/121/61/101723.P(w)1/21/51/54. Find the mean of the probability distribution of the random variable X, which10can take only the values 1, 2, and 3, given that P(1) -, P(2) -, and P(3) -5. The probabilities of a machine manufacturing 0, 1, 2, 3, 4, and 5 defective partsin one day are 0.75, 0.17, 0.04, 0.025, 0.01, and 0.005 respectively. Find the meanof the probability distribution.B. Determine the Variance and Standard Deviation of each random variable. Writeyour answer in your answer sheets.1.1234P(x)1154682.P(z)0.60.10.20.1m13573.P(m)40%25%15%20%4. The random variable X, representing the number of nuts in a chocolate bar hasthe following probability distribution. Compute the variance and standarddeviation.X1245P(x)1332110101010105. The number of items sold per day in a sari-sari store, with its correspondingprobabilities, is shown in the table below. Find the variance and standard deviationof the probability distribution.Number of Items SoldProbabilityP(x)X190.20200.20210.30220.20230.10What I Have LearnedAnswer the following questions in your own understanding.1. How to compute the mean of a discrete random variable? State

Name: 1/121/61/101723.P(w)1/21/51/54. Find the mean of the probability dist
Uploaded: 2024-03-20T07:06:41.000Z
Channel: Bartleby
Description: 1/121/61/101723.P(w)1/21/51/54. Find the mean of the probability distribution of the random variable X, which10can take only the values 1, 2, and 3, given that P(1) -, P(2) -, and P(3) -5. The probabilities of a machine manufacturing 0, 1, 2, 3, 4,

According to the Bartleby guideline only one question can be solved at one time, post the remaining…

Answered: 4. Find the mean of the probability…

Math

Probability

4. Find the mean of the probability distribution of the random variable X, which 10 1 12 can take only the values 1, 2, and 3, given that P(1) P(2) - 33' and P(3) - -- %3D

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

13. If X is a random variable with the following probability distribution , Find E(x), E(X'), V(X) and E(2X+1)² X=x -3 6 9 Total P(x) 1. T. 1 1/3 6-1/24
4
8. Be X a discrete random variable with distribution given by: Select one: a. 1/8 b. 1/4 c. 3/8 d. 5/8
A4. If random variables X and Y each have variance o? = 3 and corr(X,Y) = 0.4, what is the value of Cov(3X – 1, 2Y + 2)?
4. Let X₁ N (0,3²), X₂ N(4,4²), and X3 ~ N(-1,22) be independent random variables. Find P (X₁ + X₂ +3X3 <-8), using the table for standard normal distribution.
Q3. A random variable X is normally distributed with µ= 50 and o² = 25 . Find the %3D Probability (a) that it will fall between (i) 0 and 40 (ii) 55 and 100 (b) that it will be (i) large than 54 (ii) smaller than 57
W is a random variable with probabilities for w= 0,1 P(W = w) = {2h + k for w= 2 %3D 3k for w= 3,4 7 find the values of h and k. 10 (а) If P(W <2) = (b) Construct a probability distribution table for W. 4.
23. *An insurance policy pays an individual 100 per day for up to 3 days of hospitalization and 25 per day for each day of hospitalization thereafter. The number of days of hospitalization, X, is a discrete random variable with probability function Pr(X = k) = (1/15)(6 – k), k = 1, 2, 3, 4, 5. Calculate the expected payment for hospitalization under this policy. (213.3)
IfX is a random variable that has a uniform distribution on the interval [o, 10), then PX+ 10 27 is equal to
4.2 The probability distribution of the discrete random variable X is f(x) = 3 (*)*** Find the mean of X. 3-x (¹)ª (²³)³—ª, x = 0, 1, 2, 3.
1. If a random variable X takes the value 1,2,3,4 suchthat 2P(X = 1) = 3P(X = 2) = P(X = 3) = 5P(X = 4).Find the probability distribution of X.
5. The probability distribution of discrete random variable X is given by k for x = 1, 2, 3 x +1 P(X = x) %3D