4. Find the load resistance, RL that draws the maximum power from the circuit shown below. + Vx 1 k2 31 kO 20V 3 2k2 2Vx 1 k2

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**Problem Statement:**

4. Find the load resistance, \( R_L \), that draws the maximum power from the circuit shown below.

**Circuit Description:**

The circuit diagram includes the following components and connections:

- A voltage source of 20V is arranged in series with two resistors, each with a resistance of 1 kΩ.
- There is another voltage source labeled \( 2V_x \).
- A resistor of 1 kΩ is connected in series with the \( 2V_x \) source.
- A 2 kΩ resistor is placed parallel to the series arrangement of the 1 kΩ resistors and the 20V source.
- The load resistor \( R_L \) is connected in parallel with the 2 kΩ resistor.

**Objective:**

Calculate the value of \( R_L \) that will draw the maximum power from the circuit. This typically involves applying the Maximum Power Transfer Theorem, which states that maximum power is transferred when the load resistance \( R_L \) is equal to the Thevenin resistance of the network supplying the power to the load.
Transcribed Image Text:**Problem Statement:** 4. Find the load resistance, \( R_L \), that draws the maximum power from the circuit shown below. **Circuit Description:** The circuit diagram includes the following components and connections: - A voltage source of 20V is arranged in series with two resistors, each with a resistance of 1 kΩ. - There is another voltage source labeled \( 2V_x \). - A resistor of 1 kΩ is connected in series with the \( 2V_x \) source. - A 2 kΩ resistor is placed parallel to the series arrangement of the 1 kΩ resistors and the 20V source. - The load resistor \( R_L \) is connected in parallel with the 2 kΩ resistor. **Objective:** Calculate the value of \( R_L \) that will draw the maximum power from the circuit. This typically involves applying the Maximum Power Transfer Theorem, which states that maximum power is transferred when the load resistance \( R_L \) is equal to the Thevenin resistance of the network supplying the power to the load.
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