4. Find and classify the stationary points of each of the following functions: (a) f(x, y) = x³ + y³x² - 3y +3, (b) f(x, y) = xye-1²/2-²/2 In each case calculate the value of f(x, y) at the stationary points.

Q: The equation of the tangent line for the function f(x) = -7 – 5x at z = 7 is O y = -5(1 – 7)+42 O y…

A:

Q: Find the inflection point(s) (x,y) to the function f (x) = x²+x+1 %3D x2

A:

Q: Find y as a function of t if y(4) = 6, y (4) = 4. y = 121y" - 132y +36y = 0,

A:

Q: Let f (x) = 2x4 + 2x3 + 2x2 + 5x + 2. Fill in the missing coefficients for the derivative of f: x* +…

A: Given that :-  f is function of x f(x) = 2x⁴ + 2x³ + 2x² + 5x + 2 * We have to find  f '(x)   For…

Q: Find the derivatives of the functions

A: The derivative of the given function can be found with the help of the one-time differentiation with…

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A: It is simple derivative

Q: 2. Find all the derivatives of f, given f(x) = x8 – 5x7 + 4x6 – nx* + 3x3 + 11.

A:

Q: 5.PT. PLN has $140000 to invest. The alternative investments and the corresponding annual returns…

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A:

Q: Use the Rules of Differentiation to differentiate the following functions: a. f(x) = 2x³+ 6x d. h(x)…

A: Given data

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A: The solution of above question is written in below steps.

Q: Find yy as a function of xx if y′′′−8y′′−y′+8y=0 y(0)=4,  y′(0)=−6,  y′′(0)=130.

A:

Q: 3. Let f(x) = 2x - x². (a) Find the secant line to the graph of f passing through the points (0,0)…

A: We can find equation of secant line and tangent line .

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A: Given that x=(1,1) and y=(5,-1)

Q: Find y as a function of if y(0) = 19, y'(0) = 19, y"(0) = 4, y"(0) = 0. y(x) = y(4) 4y" + 4y = 0,

A: y(4)−4y′′′+4y′′=0y(0)=19,y′(0)=19,y′′(0)=4,y′′′(0)=0

Q: The temperature of a chemical reaction oscilates between a low of 25 C and a high ot 120 C. The…

A: Let's find.

Q: Find y as a function of a if y(0) = -2, (0) = 9, '(0) = -62. y(x) = y" - 4y" -y + 4y = 0,

A: Given that y''' -4y'' - y' + 4y = 0 ,   y(0) = - 2 y(0) = 9 '(0) = -62.

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A:

Q: Find the third derivative of the following function: f (x) = 10x³ (x + 20) 240x + 1200 dæ3 240x +…

A:

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A:

Q: Assume that ƒ′(3) = -1, g′(2) = 5, g(2) = 3, and y = ƒ(g(x)). What is y′ at x = 2?

A: Given: