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4. Evaluate the line integral f x siny dx + y dy, where C is the arc of r(t) = ti + t²j from point (-1, 1) to point (2,4). There is no shortcut, you must do the line integral. a) cos 4+cos 1+ b) +cos 4-cos 1- c) - 2 (27) + 1/ (0) + 1/25 - 12 d) (2)-(0)-26 + 1/ e) None of the above. 16 2 16 2 112112

4. Evaluate the line integral f x siny dx + y dy, where C is the arc of r(t) = ti + t²j from point (-1, 1) to point (2,4). There is no shortcut, you must do the line integral. a) cos 4+cos 1+ b) +cos 4-cos 1- c) - 2 (27) + 1/ (0) + 1/25 - 12 d) (2)-(0)-26 + 1/ e) None of the above. 16 2 16 2 112112

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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4. Evaluate the line integral fx siny dx + y dy, where C is the arc of r(t) = ti + t²j from point (-1, 1) to point (2,4). There is no shortcut, you must do the line integral. a) cos 4+cos 1+ b) +cos 4-cos 1- 2 2 c) - () + (0) + ¹/6 - d) (2)-(0)-26 + 1/2 e) None of the above 16 2 16 + 1 HIN 1 2 HINHIN 1 1 2
Transcribed Image Text:4. Evaluate the line integral fx siny dx + y dy, where C is the arc of r(t) = ti + t²j from point (-1, 1) to point (2,4). There is no shortcut, you must do the line integral. a) cos 4+cos 1+ b) +cos 4-cos 1- 2 2 c) - () + (0) + ¹/6 - d) (2)-(0)-26 + 1/2 e) None of the above 16 2 16 + 1 HIN 1 2 HINHIN 1 1 2
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