4. Determine the voltage regulation of a 2,000-V, 1-phase alternator giving a current of 100 A at 0.8 p.f. leading from the test results. Full-load current of 100 A is produced on short-circuit by a field excitation of 2.5 A. An e.m.f. of 500 V is produced on open-circuit by the same excitation. The armature resistance is 0.8 2. Draw the vector diagram. |- 8,9%]

4. Determine the voltage regulation of a 2,000-V, 1-phase alternator giving a current of 100 A at 0.8 p.f. leading from the test results. Full-load current of 100 A is produced on short-circuit by a field excitation of 2.5 A. An e.m.f. of 500 V is produced on open-circuit by the same excitation. The armature resistance is 0.8 2. Draw the vector diagram. |- 8,9%]

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter12: Power System Controls

Section: Chapter Questions

Problem 12.4P

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Similar questions

32. An alternator requires an alternating current of 2.1 A to produce on short circuit its full-load current of 50 A. The same on open-circuit an emf of 320 V. The armature resistance is 1Ohms . Find the full-load percentage regulation with a lagging p.f. of 0.6 when terminal p.d. on load is 2000 V. A. 7.2% B. 28.8% C. 3.6% D. 14.4%
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