4.) Determine the range and standard deviation of 60, 58, 62, 67, 48, 51, 72, 70
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A: It is an important part of statistics. It is widely used.
Q: not round until the final answer. Then round to the nearest hundredth as needed.)
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A: The given table is, x 471.7 659.3 740.5 790.5 781.3 1047.3…
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A: Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a…
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Q: 15. x: 471.7 659.3 740.5 790.5 781.3 1047.3 969.5…
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- 14 38. The income distribution of officers of a certain company was found to follow normal distribuiton. The average income of an officer was Rs. 15,000.00. The standard deviation of the income of officers was Rs. 5,000.00. If there were 242 officers drawing salary above Rs. 18,500.00, how many officers were there in the company ?23. Which set of numbers below will have the highest standard deviation? A. 1, 1, 2, 3, 5, 5, 9, 10, 10 B. 1, 1, 1, 2, 4, 9, 9, 19, 20 C. 2,4, 4, 6, 7, 8, 8, 10, 10 D. 3, 3, 3, 5, 5, 6, 7, 7, 7 E. 7,7,7, 7,7, 8, 8, 8, 863. According to the Internal Revenue Service, the average length of time for an individual to complete (keep records for, learn, prepare, copy, assemble, and send) IRS Form 1040 is 10.53 hours (without any attached schedules). The distribution is unknown. Let us assume that the standard deviation is two hours. Suppose we randomly sample 36 taxpayers. a. In words, X = b. In words, X = C. X ~ d. Would you be surprised if the 36 taxpayers finished their Form 1040s in an average of more than 12 hours? Explain why or why not in complete sentences. e. Would you be surprised if one taxpayer finished his or her Form 1040 in more than 12 hours? In a complete sentence, explain why.
- 14. A study using two random samples of 35 people each found that the average amount of time those in the age group of 26-35 years spent per week on leisure activities was 39.6 hours, and those in the age group of 46-55 years spent 35.4 hours Assume that the population standard deviation for those in the first age group found by previous studies is 6.3 hours, and the population standard deviation of those in the second group found by previous studies was 5.8 hours. At a = 0.05, can it be concluded that there is a significant difference in the average time each group spends on leisure activities?Calculate the means and standard deviations of:37, 26, 19, 21, 19, 25, 17 a. 3; 7.141 b. 3; 2.414 3; 6.9 23.4, 6.321 O C. d.4)Answer each question using the list of numbers provided below and use STDEV equation provided. {150,105,114,124,135,150,138,159} A) Mean B) Median C) What is the Mode= D) Standard Deviation= n(Ex?)-(Ex1)² п(п-1)
- The brain volumes (cm) of 20 brains have a mean of 1091.3 cm and a standard deviation of 121.3 cm. Use the given standard deviation and the range rule of thumb to identify the limits separating values that are significantly low or significantly high. For such data, would a brain volume of 1293.9 cm be significantly high? cm or lower Significantly low values are (Type an integer or a decimal. Do not round.) Comple Significantly high values are cm° or higher. This cou (Tune an intenor or a derimal Do not round ) Terms o Next Get more help - 8:37 PM 50°F Clear 3/27/2022 LL2. A statistic test has a mean of 78 and a standard deviation of 6. a) What is the z-score of a student who scored 89 on the test? b) What is the z-score of a student who scored 64 on the test? c) What is the z-score of a student who scored 78 on the test? d) What is the score of a student whose z-score is 1.24? e) What is the score of a student whose z-score is -.31? f) What is the score of a student whose z-score is -1? 3. For males in a certain towWn, the systolic blood pressure is normally distributed with a mean of 135 and a standard deviation of 8. a) What is the probability that a randomly selected male's systolic blood pressure will be greater than 143? b) What is the probability that a randomly selected male's systolic blood pressure will be less than 119?If the mean of five observations is 8 and their deviations about their mean :are Then the value of the .4,0,5-,3,2- =second observation is 3 O 6 O 11 O