4. DETAILS SCALCET9 2.5.037. MY NOTES ASK YOUR TEACHER Use continuity to evaluate the limit. lim In 5. SCALCET9 2.6.027. DETAILS MY NOTES ASK YOUR TEACHER Find the limit. (If the limit is infinite, enter 'co' or '-o', as appropriate. If the limit does not otherwise exist, enter DNE.) 6x - x lim X-0 x* + 8

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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4.
SCALCET9 2.5.037.
DETAILS
MY NOTES
ASK YOUR TEACHER
Use continuity to evaluate the limit.
7 - x2
lim In
X→1
1 + x
DETAILS
SCALCET9 2.6.027.
MY NOTES
ASK YOUR TEACHER
Find the limit. (If the limit is infinite, enter 'o' or '-o', as appropriate. If the limit does not otherwise exist, enter DNE.)
6x5 - x
lim
X→-0 X* + 8
5.
Transcribed Image Text:4. SCALCET9 2.5.037. DETAILS MY NOTES ASK YOUR TEACHER Use continuity to evaluate the limit. 7 - x2 lim In X→1 1 + x DETAILS SCALCET9 2.6.027. MY NOTES ASK YOUR TEACHER Find the limit. (If the limit is infinite, enter 'o' or '-o', as appropriate. If the limit does not otherwise exist, enter DNE.) 6x5 - x lim X→-0 X* + 8 5.
Expert Solution
Step 1

Solution )4) limx1ln(7 - x2/1 + x )

= ln [( 7 - 12)/( 1 + 1 )]

= ln (6/2)

= ln 3 

= 1.098

5) limx→-(6x5 - x)/(x4 + 8)

= limx→-x5(6 - x/x5)/x4(1 + 8/x4)

= limx→-∞ x ( 6 - 1/x4)/(1 + 8/x4)

= -∞( 6 - 0 )/( 1 + 0 )

= -∞

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