4. Design the foundation in Problem 3 (find the radius), for the assumptions that the failure is general, sand is dry, loading Q-6000 kN, and the factory of safety is 2.4. += 4.8 ft
4. Design the foundation in Problem 3 (find the radius), for the assumptions that the failure is general, sand is dry, loading Q-6000 kN, and the factory of safety is 2.4. += 4.8 ft
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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PLEASE ONLY SOLVE PROBLEM 4 Please explain the theory and concept behind this problem so I can understand, please show clear and neat handwriting/calculations
![3.Define the allowable bearing capacity of a circular foundation of a radius 2R=10 ft using the
Terzaghi's bearing capacity equation for a local failure. In your calculations assume two scenarios:
a) that the ground water table matches the bottom of the foundation, and b) that the ground water
table is 6 ft below the bottom of the foundation. Use a factor of safety of 2.8, and the dry unit weight
above the ground water table.
6 ft
10 ft
20 ft
2R
ROCK
SAND
D
= 36
G=2.67
e = 0.6
CLAY
C=0.75
e = 0.9
Y sa: 132 pcf
6 ft
a) gall.
B) gall = 1565psf
= 1502 psfi
4. Design the foundation in Problem 3 (find the radius), for the assumptions that the failure is
general, sand is dry, loading Q-6000 kN, and the factory of safety is 2.4.
+= 4.8 ft](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F78a1cdca-9a2c-4803-aedc-ba4e0e310e87%2Fec49d332-aeda-45aa-93e6-ca43192ed3a5%2Fmgjsh8o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3.Define the allowable bearing capacity of a circular foundation of a radius 2R=10 ft using the
Terzaghi's bearing capacity equation for a local failure. In your calculations assume two scenarios:
a) that the ground water table matches the bottom of the foundation, and b) that the ground water
table is 6 ft below the bottom of the foundation. Use a factor of safety of 2.8, and the dry unit weight
above the ground water table.
6 ft
10 ft
20 ft
2R
ROCK
SAND
D
= 36
G=2.67
e = 0.6
CLAY
C=0.75
e = 0.9
Y sa: 132 pcf
6 ft
a) gall.
B) gall = 1565psf
= 1502 psfi
4. Design the foundation in Problem 3 (find the radius), for the assumptions that the failure is
general, sand is dry, loading Q-6000 kN, and the factory of safety is 2.4.
+= 4.8 ft
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