4. Consider the reaction 2HBr (g) At 425°C, Keq = 4.18 x 109. If the container has 0.20atm of HBr, 0.010atm of H2 and 0.010 atm of Br2, which direction will the reaction proceed? Why? Br2(g) H2(g) + 2Cl (aq) Pb2+ 5. Consider the reaction PbCl2(s) K sp 1.17 x 105. Determine the equilibrium concentrations of Pb2 and Cl if PbCl2 is dissolved in 0.100M NaCl + (aq) = 6. Using the given information to calculate the new Keq: а. 2HI (g) What is the new Keq for H2(g) H2(g) H2(g) with Keq = 12.5 2HI (g) H2(g) b. 2HI (g) H2(g) What is the new Keq for 1/2H2(g) H2(g) with Keq = 12.5 HI (g) 1/2H2() с. (1) Hb(a) (2) Hb(aq) O2(aq) СО(аq) +> НЬО2(аq) НЬС Оад) Ксg Кeg 1.8 306 СО (аq) + HbCO(aq) HЬО2даg) + O2(aq) Ke? + =

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4. Consider the reaction 2HBr (g)
At 425°C, Keq = 4.18 x 109. If the container has 0.20atm of HBr, 0.010atm of H2 and
0.010 atm of Br2, which direction will the reaction proceed? Why?
Br2(g)
H2(g)
+
2Cl (aq)
Pb2+
5. Consider the reaction PbCl2(s)
K sp 1.17 x 105. Determine the equilibrium concentrations of Pb2 and Cl if PbCl2 is
dissolved in 0.100M NaCl
+
(aq)
=
6. Using the given information to calculate the new Keq:
а. 2HI (g)
What is the new Keq for
H2(g)
H2(g)
H2(g) with Keq = 12.5
2HI (g)
H2(g)
b. 2HI (g)
H2(g)
What is the new Keq for
1/2H2(g)
H2(g) with Keq = 12.5
HI (g)
1/2H2()
с.
(1) Hb(a)
(2) Hb(aq)
O2(aq)
СО(аq) +>
НЬО2(аq)
НЬС Оад)
Ксg
Кeg
1.8
306
СО (аq) +
HbCO(aq)
HЬО2даg) +
O2(aq) Ke?
+
=
Transcribed Image Text:4. Consider the reaction 2HBr (g) At 425°C, Keq = 4.18 x 109. If the container has 0.20atm of HBr, 0.010atm of H2 and 0.010 atm of Br2, which direction will the reaction proceed? Why? Br2(g) H2(g) + 2Cl (aq) Pb2+ 5. Consider the reaction PbCl2(s) K sp 1.17 x 105. Determine the equilibrium concentrations of Pb2 and Cl if PbCl2 is dissolved in 0.100M NaCl + (aq) = 6. Using the given information to calculate the new Keq: а. 2HI (g) What is the new Keq for H2(g) H2(g) H2(g) with Keq = 12.5 2HI (g) H2(g) b. 2HI (g) H2(g) What is the new Keq for 1/2H2(g) H2(g) with Keq = 12.5 HI (g) 1/2H2() с. (1) Hb(a) (2) Hb(aq) O2(aq) СО(аq) +> НЬО2(аq) НЬС Оад) Ксg Кeg 1.8 306 СО (аq) + HbCO(aq) HЬО2даg) + O2(aq) Ke? + =
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