4. Consider the cell below. Draw the cell (using two compartments separated by a porous plate) then answer the questions pertaining to the cell. Al | Al(NO3)3 1.0M || CrCl3 1.0M; CrCl21.0M | Pt a) What will be the spontaneous reaction? b) What will be the cell voltage? c) Show, using an arrow, the direction of flow of the elections through the wire. d) Label the anode and the cathode. e) What is the sign of the anode? f) Show, using arrows and formulas, the direction of flow of ions through the porous plate.
4. Consider the cell below. Draw the cell (using two compartments separated by a porous plate) then answer the questions pertaining to the cell. Al | Al(NO3)3 1.0M || CrCl3 1.0M; CrCl21.0M | Pt a) What will be the spontaneous reaction? b) What will be the cell voltage? c) Show, using an arrow, the direction of flow of the elections through the wire. d) Label the anode and the cathode. e) What is the sign of the anode? f) Show, using arrows and formulas, the direction of flow of ions through the porous plate.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:4. Consider the cell below. Draw the cell (using two compartments separated by a
porous plate) then answer the questions pertaining to the cell.
Al | Al(NO3)3 1.0M || CrCl3 1.0M; CrCl21.0M | Pt
a) What will be the spontaneous reaction?
b) What will be the cell voltage?
c) Show, using an arrow, the direction of flow of the elections through the wire.
d) Label the anode and the cathode.
e) What is the sign of the anode?
f) Show, using arrows and formulas, the direction of flow of ions through the
porous plate.
Expert Solution

Step 1
Since your question has multiple sub-parts, we will solve first three sub-part for you. If you want remaining sub-parts to be solved, then please resubmit the whole question and specify those sub-parts which you want us to solve.
Step 2
For the reaction to be spontaneous, its EMF should be positive. The reactions taking place will be as follows:
Multiplying equation (2) by 3 so as to cancel the electrons.
The overall spontaneous reaction taking place will be as follows :
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