4. Consider following figure. TCP sender wants to send a total of 20 segments to the receiver and sendsan initial window of 5 segments at t = 1, 2, 3, 4, & 5, respectively. Suppose the initial value of thesequence number is 50 and every segment sent to the receiver each contains 512 bytes. The delaybetween the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8,and an ACK for this segment arrives at t = 15.→ Show Transcribed TextTCP sendert = 1t = 2t = 3-t = 4t=5+t = 15-t= 16-t = 17t = 18t = 19data segmentdata segmentdata segmentdata segment →→*datasegmentACK segmentACK segmentACK segmentACK segmentงTCP receivert = 8t = 9t = 10t = 11t = 12As shown in the figure above, 4th segment is lost between sender and receiver, but none of the ACKSare lost. Assume there are no timeouts and any out of order segments received are dropped. Answerthe following questions:a) What are the sequence numbers for each of the 20 data segments

For the given scenario, we need to find the sequence numbers for each of the 20 data segments.

4. Consider following figure. TCP sender wants to send a total of 20 segments to the receiver and sends an initial window of 5 segments at t = 1, 2, 3, 4, & 5, respectively. Suppose the initial value of the sequence number is 50 and every segment sent to the receiver each contains 512 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for this segment arrives at t = 15. Show Transcribed Text TCP sender t=2 t=3 t=4 t=5 t=15 t = 16 t = 17 t = 18 t = 19 data segment data segment data segment data segment* data segment ACK segment ACK segment ACK segment ACK segment 3 C TCP receiver t = 8 t=9 t = 10 t = 11 t = 12 As shown in the figure above, 4th segment is lost between sender and receiver, but none of the ACKS are lost. Assume there are no timeouts and any out of order segments received are dropped. Answer the following questions: a) What are the sequence numbers for each of the 20 data segments

4. Consider following figure. TCP sender wants to send a total of 20 segments to the receiver and sends an initial window of 5 segments at t = 1, 2, 3, 4, & 5, respectively. Suppose the initial value of the sequence number is 50 and every segment sent to the receiver each contains 512 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for this segment arrives at t = 15. Show Transcribed Text TCP sender t=2 t=3 t=4 t=5 t=15 t = 16 t = 17 t = 18 t = 19 data segment data segment data segment data segment* data segment ACK segment ACK segment ACK segment ACK segment 3 C TCP receiver t = 8 t=9 t = 10 t = 11 t = 12 As shown in the figure above, 4th segment is lost between sender and receiver, but none of the ACKS are lost. Assume there are no timeouts and any out of order segments received are dropped. Answer the following questions: a) What are the sequence numbers for each of the 20 data segments

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter9: Computer Networks

Section: Chapter Questions

Problem 15VE

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Consider the figure below in which a TCP sender and receiver communicate over a connection in which the sender->receiver segments may be lost. The TCP sender sends an initial window of 5 segments. Suppose the initial value of the sender->receiver sequence number is 362 and the first 5 segments each contain 638 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t=8. As shown in the figure below, 3 of the 5 segment(s) are lost between the segment and receiver.
Consider the figure below in which a TCP sender and receiver communicate over a connection in which the segments can be lost. The TCP sender wants to send a total of 10 segments to the receiver and sends an initial window of 5 segments at t = 1, 2, 3, 4, and 5, respectively. Suppose the initial value of the sequence number is 151 and every segment sent to the receiver each contains 612 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for this segment arrives at t = 15. As shown in the figure, 1 of the 5 segments is lost between the sender and the receiver, but none of the ACKs are lost. Assume there are no timeouts and any out of order segments received are thrown out.
Consider the figure below in which a TCP sender and receiver communicate over a connection in which the segments can be lost. The TCP sender wants to send a total of 10 segments to the receiver and sends an initial window of 5 segments at t = 1, 2, 3, 4, and 5, respectively. Suppose the initial value of the sequence number is 151 and every segment sent to the receiver each contains 612 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for this segment arrives at t = 15. As shown in the figure, 1 of the 5 segments is lost between the sender and the receiver, but none of the ACKs are lost. Assume there are no timeouts and any out of order segments received are thrown out.
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Question 8 Suppose that a TCP sender is sending segments with 100 bytes of payload. It sends five segments with sequence numbers 100, 200, 300, 400, and 500. Suppose that the segment with sequence number 300 is lost. What are the ACK values that the receiver returns to the sender after each of the four received segments are received. After receiving segment 100, the receiver responds with an ACK with value: After receiving segment 200, the receiver responds with an ACK with value: After receiving segment 400, the receiver responds with an ACK with value: After receiving segment 500, the receiver responds with an ACK with value: After receiving the retransmitted segment, the receiver responds with an ACK with value:
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