4 5 6 4. Complete the Pair the gametes inside the boxes.AbabавАВAaBbАВAABBAAbbAaBbAbaaBBaaBbавabAaBbAabb5. Complete the phenotype on each box.АВAbавabAABB(black hair andbrown eyes)AaBb(black hair andbrown eyes)ABAAbb(black hair andblue eyes)AaBb(black hair andbrown eyes)aaBB(blonde hair andbrown eyes)AbaaBb(blonde hair andbrown eyes)aBAaBb(black hair andbrown eyes)Aabb(black hair andblue eyes)abYTIVITOA6. Identify the genotypic and phenotypic ratios.dnoblGR =PR =ow for hair color and eye color. For the hair color, the allele for black hair (A) is dominantover the allele for blonde hair (a). For the eye color, the allele for brown eyes (B) isdominant over the allele for blue eyes (b).> A father has black hair (Aa) and brown eyes (Bb), and the mother has black hair(Aa) and brown eyes too (Bb).BA> Both are heterozygous for the two traits.DAA Now, let's test yourunderstanding about thistopic.d8eon lard obnoki)ddeADirections: Answer the following questions below based onthe given situations about the Dihybrid Cross.ACTIVITY: 21. Identify the genotypes of the parents.aoitsi sig doneriq bns olqvioneg ertt yitnebl aFather (AaBb)Mother (AaBb)2. Determine the possibie gamete combinations.Father -tebaaMMother -3. Complete the possible gamete combinations of the parents on the top and on the left side of thesquare.pedhoash nollepoiges loABabAbaBnl colsils to

Name: 4 5 6 4. Complete the Pair the gametes inside the boxes.AbabавАВAaBbАВ
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Description: 4 5 6 4. Complete the Pair the gametes inside the boxes.AbabавАВAaBbАВAABBAAbbAaBbAbaaBBaaBbавabAaBbAabb5. Complete the phenotype on each box.АВAbавabAABB(black hair andbrown eyes)AaBb(black hair andbrown eyes)ABAAbb(black hair andblue eyes)AaBb(blac

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4. Complete the Pair the gametes inside the boxes. Ab ab ав АВ AaBb АВ AABB AAbb AaBb Ab aaBB aaBb ав ab AaBb Aabb 5. Complete the phenotype on each box. AB Ab aB ab AABB (black hair and brown eyes) AaBb (black hair and brown eyes) AB AaBb (black hair and brown eyes) aaBB (blonde hair and brown eyes) AAbb (black hair and blue eyes) Ab aB aaBb (blonde hair and brown eyes) Aabb (black hair and blue eyes) ab AaBb (black hair and brown eyes) YTIVITOA 6. Identify the genotypic and phenotypic ratios. GR = PR = 阳 ow

4. Complete the Pair the gametes inside the boxes. Ab ab ав АВ AaBb АВ AABB AAbb AaBb Ab aaBB aaBb ав ab AaBb Aabb 5. Complete the phenotype on each box. AB Ab aB ab AABB (black hair and brown eyes) AaBb (black hair and brown eyes) AB AaBb (black hair and brown eyes) aaBB (blonde hair and brown eyes) AAbb (black hair and blue eyes) Ab aB aaBb (blonde hair and brown eyes) Aabb (black hair and blue eyes) ab AaBb (black hair and brown eyes) YTIVITOA 6. Identify the genotypic and phenotypic ratios. GR = PR = 阳 ow

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter3: Transmission Of Genes From Generation To Generation

Section: Chapter Questions

Problem 36QP

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Let’s look at hair texture. Some people have curly hair, some have straight hair and some express a traitthat is in-between (Incomplete Dominance), or wavy hair. Therefore curly and straight are bothhomozygous and wavy is the expression of the heterozygous condition. Instead of using capital and lowercase letters, we’ll add a prime (`) to the letter. This is because one is not dominant over the other, andthey will both contribute to the phenotype. We can use H to indicate curly hair and H` to indicate straighthair.Given this information, complete the square: Parent Phenotype(appearance) Genotype(alleles) 1 Curly hair HH 2 Straight hair H'H' Do you remember where the alleles of each parent go?Parents: Offspring: Genotypes: Phenotypes: What are the potential phenotypes and genotypes of the offspring?
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CO-DOMINANCE/I... % Ø Oll ^ 6- 3. A homozygous red gummy bear is crossed with a homozygous yellow gummy bear (red and yellow mixed together make orange). You predicted that all the offspring will be orange gummy bears. Create a Punnett Square, then explain if your prediction was correct. 13 r y 2 / 3 | - h ? & 71 u * 82 87% i + | © k ( 93 O D § ) 014 Р 11 -½ { [ [ ^ 11 = ¾ 11 8 '{' \
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Mendel is growing flowers. Pure red flowers have a pair of R genes. Pure whiteflowers have a pair of w genes. Red is dominant to white.(a) Write the Punnett square with a pure red parent cross-fertilized with a pure white parent.(b) Write a second Punnett square of the offspring of the preceeding question cross-fertilizedwith a pure white flower.(c) What is the probability that a flower from the second fertilization is pure white? (Writethe probability as a fraction in reduced form.)
Homozygous dominant parent (PP), and a Homozygous recessive or just simply say recessive parent (pp): a. Fill in the Punnett square. Each box represents a genotype possibility for an offspring. b. Place the allele donated by each parent in the corresponding box. Now list the possible genotypes and their corresponding phenotype. c. If an individual's genotype is heterozygous, the dominant trait will be expressed in the phenotype. Give the percent possible for the phenotypes. P P p p Genotype: ______________ Phenotype: ______________ Phenotype % probable: __________ 2. Cross between a Homozygous dominant parent (PP) and a Heterozygous parent (Pp). Fill in as in step one. 3. Cross between a Heterozygous parent (Pp), and another Heterozygous parent (Pp). Fill-in as before. 4. Test cross: A test cross is between a recessive parent (pp), and a Heterozygous parent…
I. ACTIVITIES AND EXERCISES-Let's Try Thesef () Solve for the following completely by following the step by step process in solving for Punnett Squares. Place your answers on the corresponding blanks. White skin tone is incompletely dominant with Dark Skin tone. A heterozygous skin tone allele will form Tan colored skin. What is/are the possible phenotype/s of the children from a white skin toned man and a tan skin toned woman? Traits: White Phenotype/s: Dark => Tan == Test Cross: Punnett Square 14) 2) 3) 8) 9) 5) 10) 12) 7) 11) Teacher: 13)