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4. Can you confidently determine if your molarities are precise? Explain why or why not.

4. Can you confidently determine if your molarities are precise? Explain why or why not.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Part 2: Use the volume of NaOH used and the molarity of NaOH to calculate moles of NaOH reacted Use stoichiometry to determine moles of the acid reacted. ● ● Divide moles acid by volume of the sample used to get molarity (mol/L), Average the molarity for all trials. 0.1137 Data Volume of HCI Initial Burette Reading Final Burette Reading Net Volume NaOH Moles NaOH Used Moles HCI Used Molarity of HCI Average Molarity of HCI 0.0084. Average Molaity Trial 1 Trial 2 10AL 0.15 Me 8.58 8.43 B5 0.000958 BULA 1200009% 34 $80.000958 60.874 Males Hel Net volun 0.000 9/8.43 0.01 0.958 1.284 01137 lome 8.5PML 15.88 ML 7.3m2 0.000830 2007 0.00083. 0.083 Na OH Trial 3 10 ML 15.88ML 23.4512 7.3ML 7.7712 23. 0.000983 468 0.02973 0.0883 10ML = 0.01L Trial 4 10ML 23.65ML 30.75ML 7.1072 0-000883 0.000807 0.0001 0.000807 0807 Trial 5 10 ML 30:35A2 37.28m2 4.53m2 0.000742 0.000742 0.0742
Transcribed Image Text:Part 2: Use the volume of NaOH used and the molarity of NaOH to calculate moles of NaOH reacted Use stoichiometry to determine moles of the acid reacted. ● ● Divide moles acid by volume of the sample used to get molarity (mol/L), Average the molarity for all trials. 0.1137 Data Volume of HCI Initial Burette Reading Final Burette Reading Net Volume NaOH Moles NaOH Used Moles HCI Used Molarity of HCI Average Molarity of HCI 0.0084. Average Molaity Trial 1 Trial 2 10AL 0.15 Me 8.58 8.43 B5 0.000958 BULA 1200009% 34 $80.000958 60.874 Males Hel Net volun 0.000 9/8.43 0.01 0.958 1.284 01137 lome 8.5PML 15.88 ML 7.3m2 0.000830 2007 0.00083. 0.083 Na OH Trial 3 10 ML 15.88ML 23.4512 7.3ML 7.7712 23. 0.000983 468 0.02973 0.0883 10ML = 0.01L Trial 4 10ML 23.65ML 30.75ML 7.1072 0-000883 0.000807 0.0001 0.000807 0807 Trial 5 10 ML 30:35A2 37.28m2 4.53m2 0.000742 0.000742 0.0742
2. What affect, in any, would this error have on the molarity of acid in part two? Would you calculate a molarity that is higher than/lower than/the same as the actual molarity? Explain your reasoning. 3. Can you confidently determine if your molarities are accurate? Explain why or why not. 4. Can you confidently determine if your molarities are precise? Explain why or why not.
Transcribed Image Text:2. What affect, in any, would this error have on the molarity of acid in part two? Would you calculate a molarity that is higher than/lower than/the same as the actual molarity? Explain your reasoning. 3. Can you confidently determine if your molarities are accurate? Explain why or why not. 4. Can you confidently determine if your molarities are precise? Explain why or why not.
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