Did I do this right? 4. Çalculate the work done when 50.0 g of tin dissolve in excess acid at 1.00 atm and 25 °C:W=-1P)(AVsM=50-0gP=1.00atmT= 26°C - 25+273-298kSn(s) + 2H*(aq)Sn2*(aq), + H2(g)Assume ideal gas behavior. Molarmassof Sh - |8-719/molImoltH2RT50-0118-7V==0.421molXo.0821X29EK50.06 Imoisn-= 0.421molespV=nRT%3D118.795n| ImelsnA-0121X8.314X298=1043J| atm=10.30L volunme gal releaseol=10-305

Answer: Initially there is no gas in the container and later on through the chemical reaction…

4. Calculate the work done when 50.0 g of tin dissolve in excess acid at 1.00 atm and 25 °C: M-50-09 P=1.00atm T= 26°C - 25+273-298K Sn(s) + 2H*(aq) Sn2*(aq) + H2(g)

4. Calculate the work done when 50.0 g of tin dissolve in excess acid at 1.00 atm and 25 °C: M-50-09 P=1.00atm T= 26°C - 25+273-298K Sn(s) + 2H(aq) Sn2(aq) + H2(g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Did I do this right?

4. Çalculate the work done when 50.0 g of tin dissolve in excess acid at 1.00 atm and 25 °C:
W=-1P)(AVs
M=50-0g
P=1.00atm
T= 26°C - 25+273-298k
Sn(s) + 2H*(aq)
Sn2*(aq), + H2(g)
Assume ideal gas behavior. Molarmassof Sh - |8-719/mol
ImoltH2
RT
50-0
118-7
V=
=0.421molXo.0821X29EK
50.06 Imoisn
-= 0.421moles
pV=nRT
%3D
118.795n| Imelsn
A-0121X8.314X298=1043J
| atm
=10.30L volunme gal releaseol
=10-305

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