4. Calculate the real or reactive power delivered to each passive element. Also, determine the real and reactive powers supplied by each source. A 110/28 V jan
Load flow analysis
Load flow analysis is a study or numerical calculation of the power flow of power in steady-state conditions in any electrical system. It is used to determine the flow of power (real and reactive), voltage, or current in a system under any load conditions.
Nodal Matrix
The nodal matrix or simply known as admittance matrix, generally in engineering term it is called Y Matrix or Y bus, since it involve matrices so it is also referred as a n into n order matrix that represents a power system with n number of buses. It shows the buses' nodal admittance in a power system. The Y matrix is rather sparse in actual systems with thousands of buses. In the power system the transmission cables connect each bus to only a few other buses. Also the important data that one needs for have a power flow study is the Y Matrix.
Types of Buses
A bus is a type of system of communication that transfers data between the components inside a computer or between two or more computers. With multiple hardware connections, the earlier buses were parallel electrical wires but the term "bus" is now used for any type of physical arrangement which provides the same type of logical functions similar to the parallel electrical bus. Both parallel and bit connections are used by modern buses. They can be wired either electrical parallel or daisy chain topology or are connected by hubs which are switched same as in the case of Universal Serial Bus or USB.
![### Problem 4
**Calculate the real or reactive power delivered to each passive element. Also, determine the real and reactive powers supplied by each source.**
#### Explanation:
The image contains a circuit diagram with a combination of resistive and reactive elements powered by a current source and a voltage source.
#### Description of the Circuit:
1. **Current Source:** A 5∠20° A current source is present on the left side of the circuit.
2. **Series Components:**
- There is a resistor of 10Ω.
- An inductor of j5Ω is connected in series with the 10Ω resistor.
3. **Parallel Components:**
- An 8Ω resistor.
- A capacitor of -j8Ω.
4. **Voltage Source:** A sinusoidal voltage source of 110∠28° V is present on the right side of the circuit.
#### Steps to Solve:
1. **Calculate the Impedance in the Series Path:**
\[
Z_{\text{series}} = 10Ω + j5Ω
\]
2. **Calculate the Impedance in the Parallel Path:**
\[
Z_{\text{parallel}} = \left( 8Ω \parallel -j8Ω \right)
\]
- Use the formula for parallel impedance:
\[
Z_{\text{parallel}} = (Z_1 Z_2) / (Z_1 + Z_2)
\]
3. **Determine Equivalent Impedance of the Entire Circuit:**
\[
Z_{\text{total}} = Z_{\text{series}} + Z_{\text{parallel}}
\]
4. **Calculate the Voltage Across Each Element:**
- Use Ohm's Law \( V = IZ \) where required to find the voltage across each component.
5. **Calculate the Real and Reactive Power for Each Component:**
- Real Power (P): \( P = VI \cos(\phi) \)
- Reactive Power (Q): \( Q = VI \sin(\phi) \)
6. **Determine the Power Supplied by Each Source:**
- For the current source, determine \( P \) and \( Q \) using the supplied current and voltage drop across the elements.
- For the voltage source, use the supplied voltage and current through the components.
#### Useful Equations:
- **Ohm's Law](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Facdec92e-028d-4f37-af60-841922a4cee5%2F917c7f76-17ad-40fb-985b-3e2022366902%2Fvgm0b08_processed.png&w=3840&q=75)
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 7 images
