4. Assume that you have 0.001 Fe* and 0.002 Fe2* (i.e., the solution contains Ferrous and Ferric chloride) in the solution and then use the Nernst equation to calculate the Nernst potential vs. SCE for each half cell reaction. Two parts: One half cell reaction is Fe3+ + e- = Fe²*. The second half cell reaction is Fe = Fe2+ + 2e-. Which one is the anode, which one the cathode?

4. Assume that you have 0.001 Fe* and 0.002 Fe2* (i.e., the solution contains Ferrous and Ferric chloride) in the solution and then use the Nernst equation to calculate the Nernst potential vs. SCE for each half cell reaction. Two parts: One half cell reaction is Fe3+ + e- = Fe²*. The second half cell reaction is Fe = Fe2+ + 2e-. Which one is the anode, which one the cathode?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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