4. Assume that each variable of the function in y is a function of time t. Desmos | Graphing Calculator https://www.desmos.com/calculator Car 1 starts on the graph of y = e^x at the point (0,1) and car 2 starts on the graph of Y = 3x-2 at the point (0,-2) y= e* and distance is measured in miles. If both cars start moving to the right at the same time in such a way that Sx =D1 St y= 3x-2 |(0,1) mile/minute, -05 (g-2) at what rate is the distance between the cars changing when t= 3 minutes? (You may assume that the vertical and the shortest distances are identical.)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Title: Analyzing the Rates of Change in Function-Based Movement**

---

**Problem Statement:**

4. Assume that each variable of the function in \( y \) is a function of time \( t \).

**Graph Description:**

The graph displays two functions:
- \( y = e^x \), an exponential curve.
- \( y = 3x - 2 \), a straight line with a slope of 3.

Each function has a distinct starting point:
- The curve \( y = e^x \) passes through the point \((0, 1)\).
- The line \( y = 3x - 2 \) passes through the point \((0, -2)\).

**Scenario:**

- Car 1 starts on the graph of \( y = e^x \) at the point \((0, 1)\).
- Car 2 starts on the graph of \( y = 3x - 2 \) at the point \((0, -2)\).
- Distances are measured in miles.

Both cars move to the right simultaneously with a speed governed by:

\[
\frac{\delta x}{\delta t} = 1 \text{ mile/minute}
\]

**Question:**

At what rate is the distance between the cars changing when \( t = 3 \) minutes?

*(You may assume that the vertical and the shortest distances are identical.)*

**Explanation:**

This problem involves calculating the rate at which the distance between two dynamically moving points, represented by cars, is changing as time passes. The cars follow their respective paths: an exponential curve and a linear path. This involves a conceptual understanding of derivatives and rate of change in coordinate geometry.

---
Transcribed Image Text:**Title: Analyzing the Rates of Change in Function-Based Movement** --- **Problem Statement:** 4. Assume that each variable of the function in \( y \) is a function of time \( t \). **Graph Description:** The graph displays two functions: - \( y = e^x \), an exponential curve. - \( y = 3x - 2 \), a straight line with a slope of 3. Each function has a distinct starting point: - The curve \( y = e^x \) passes through the point \((0, 1)\). - The line \( y = 3x - 2 \) passes through the point \((0, -2)\). **Scenario:** - Car 1 starts on the graph of \( y = e^x \) at the point \((0, 1)\). - Car 2 starts on the graph of \( y = 3x - 2 \) at the point \((0, -2)\). - Distances are measured in miles. Both cars move to the right simultaneously with a speed governed by: \[ \frac{\delta x}{\delta t} = 1 \text{ mile/minute} \] **Question:** At what rate is the distance between the cars changing when \( t = 3 \) minutes? *(You may assume that the vertical and the shortest distances are identical.)* **Explanation:** This problem involves calculating the rate at which the distance between two dynamically moving points, represented by cars, is changing as time passes. The cars follow their respective paths: an exponential curve and a linear path. This involves a conceptual understanding of derivatives and rate of change in coordinate geometry. ---
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