4. Any cable hanging between two poles must follow a specific curve. To simplify calculations, we choose a coordinate system so that the locations of the two poles are at x = -B and x=+B. The curve has equation y = C + A cosh(). Find an integral expression for the length of the cable, and evaluate that integral. (Your final answer will be in terms of A and B.)
4. Any cable hanging between two poles must follow a specific curve. To simplify calculations, we choose a coordinate system so that the locations of the two poles are at x = -B and x=+B. The curve has equation y = C + A cosh(). Find an integral expression for the length of the cable, and evaluate that integral. (Your final answer will be in terms of A and B.)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:4. Any cable hanging between two poles must follow a specific curve. To simplify calculations,
we choose a coordinate system so that the locations of the two poles are at x = -B and
x=+B. The curve has equation
(2).
Find an integral expression for the length of the cable, and evaluate that integral. (Your final
answer will be in terms of A and B.)
y=C+ Acosh(
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