4. An insulating semicircular arc of radius R consists of two quarters. One quarter has a total charge -Q uniformly distributed and the other half +Q. Find the electric field at the center P
4. An insulating semicircular arc of radius R consists of two quarters. One quarter has a total charge -Q uniformly distributed and the other half +Q. Find the electric field at the center P
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![4. An insulating semicircular arc of radius R consists of two quarters. One quarter has a total
charge -Q uniformly distributed and the other half +Q. Find the electric field at the center P
Id=1= k ldq|
R²
e =
Ex=SdEx = S-2/del cose
=
dEx=-2 IdEl cose
J-₂00
1-2 cos oldE)
= S-2 cosok d
R2
2Q
TR
I cos (o) (k 20 do)
R2
de
Jeans
=Q₂ =de
Пр ds
dq →
edo
Sin (45)
Cos (45°)
+++
rdq
dq=/2Q R de
TR
use thi
kemisen
S=RO
1
const
ds =R do](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F18172341-1844-47d5-991d-98dd00d1ba57%2Fb7a25606-637c-41c2-9097-def30c953769%2F6w6vq7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4. An insulating semicircular arc of radius R consists of two quarters. One quarter has a total
charge -Q uniformly distributed and the other half +Q. Find the electric field at the center P
Id=1= k ldq|
R²
e =
Ex=SdEx = S-2/del cose
=
dEx=-2 IdEl cose
J-₂00
1-2 cos oldE)
= S-2 cosok d
R2
2Q
TR
I cos (o) (k 20 do)
R2
de
Jeans
=Q₂ =de
Пр ds
dq →
edo
Sin (45)
Cos (45°)
+++
rdq
dq=/2Q R de
TR
use thi
kemisen
S=RO
1
const
ds =R do
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