4. An infinitely long wire has been bent into the hairpin-like shape shown below. The curved part of the wire is a semicircle of radius R. Point P is the center of the semicircle. The wire carries a current I in the direction indicated by the purple arrows. R Find the magnetic field at point P. P I
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- A uniform magnetic field points in the +x direction and has a magnitude of 0.500Tesla. The current in the wire segment shown is carry 2.25 Amps, has a length of 1.5 meters and the angle is =30 degrees above the horizontal as shown. a.Find the directionof the force on the wiresegment. b.Find the magnitude of the force on the wiresegment. c.Find the torque on the wire segmentabout its centerA uniform magnetic field is directed as shown in the accompanying diagram. A particle, moving in the plane of the diagram, follows a counterclockwise spiral of increasing radius as shown. What is a possible explanation for the particle's trajectory? HO The particle is negatively charged and speeding up. The particle is negatively charged and slowing down. The particle is positively charged and slowing down. O The particle is uncharged and speeding up. O The particle is positively charged and speeding up. particle BAn electron moves with a speed of 2.5×107 m/sm/s in the directions shown in the figure. A 0.40 TT magnetic field points in the positive x-direction.(Figure 1) A. What is the magnitude of the magnetic force in figure (a)? F= B. What is the direction of the magnetic force in figure (a)? a. +z direction b. -z direction c. +zy direction d. -zy direction C. What is the magnitude of the magnetic force in figure (b)? F = D. What is the direction of the magnetic force in figure (b)? a. +zy direction b. -zy direction c. +z direction d. -y direction
- 9. Two long, straight wires are separated by distance, d = 21.0 cm. The wires carry currents of I₁ 2.50 A and I2 = 8.50 A in the same directions, as shown in the figure. Find the magnitude of the net magnetic cm, r2 = field at point (B). Let r₁ = 13.0 7.00 cm, and r3 = 14.0 cm. T r₂ OSS SS 09- A B ssf60 ssf60 ssf60 s60 ssf60 ssf60 ssf60 ssf60 f60 ssf60 ssf60 ssf60 ssf60 ssf60 ssfo d £60 *$$ (9js8 09888 f60 s: 60 ssf60 ssf60 ssf60 ssf60 ssf60 ssf60 f60 ssf f60 ss$60 ssf60 ssf60 ssf60 ssf60 ssf60 ssYour answer is partially correct. In the figure, four long straight wires are perpendicular to the page, and their cross sections form a square of edge length a = 4.67 cm. Each wire carries 11.2 A, and all the currents are out of the page. What is the magnitude of the net magnetic force per unit length on wire 1? Number i 0.00085 Units N/m aPP5
- In the figure, four long straight wires are perpendicular to the page, and their cross sections form a square of edge length a = 17 cm. The currents are out of the page in wires 1 and 4 and into the page in wires 2 and 3, and each wire carries 29 A. What is the magnitude of the net magnetic field at the square's center? a 3A negatively charged ion with an excess electron moving with a velocity vx = 1.095 x103 m/s is introduced into a magnetic field Bz = 4 mTesla perpendicular to the ion’s direction of motion. The ion travels in a semi circle of diameter d = 8 cm before striking a detector. What is the ion? Select one: a. 32S b. 12C c. 16O d. 14NAn oxygen-16 with a mass of 2.656 × 10-26 kg travels at 6.50 × 106 m/s perpendicular to a 1.2- tesla magnetic field, which makes it move in a circular arc with a 0.898-meter radius. Hint a. What is the amount of postive charge on the ion? Amount of charge on the ion is x 10-¹⁹ C. b. Based on your answer in (a), how many electrons has this oxygen-16 lost? This oxygen-16 lost electrons.
- In the figure, point P, is at perpendicular distance R = 28.7 cm from one end of straight wire of length L = 14.6 cm carrying current i = 0.756 A. (Note that the wire is not long.) What is the magnitude of the magnetic field at P2? P R R L. Number i UnitsThe instantaneous position of an electron with velocity v is shown in the figure. What is the the magnitude and direction of the magnetic field at point P? -lel O A. O B. O C. K V O D. но ev 8n r2 Ho ev 8π p2 into the page out of the page Ho V3ev 8T p² FIM ', Ho √3ev 8T p² into the page out of the page PIn an old-fashioned television, a beam of electrons is accelerated to a speed of 2.3 × 106 m /s and then directed to the flat screen, a distance d = 0.05 m from the end of the accelerator, using magnets, as shown in the figure below. The mass of an electron is 9.1 × 10-31 kg. a. An electron, having just left the accelerator and traveling in the x direction, enters a region of uniform magnetic field, B = 1.5 x 10-4 T in the y direction. What is the force on the electron due to the magnetic field? Be sure to specify both the magnitude and direction. b. What is the radius of curvature of the path of the electron as it moves from the accelerator to the screen? c. With what speed does the electron hit the screen? d. How far from the center of the screen does the electron hit? That is, how far is the electron deflected by the magnetic field? В y accelerator d