4. A round, horizontal, simply supported steel bar is subject to an axial compressive load, P = 5 kN, at each end acting at its centroid. Due to space constraints, the maximum deflection of the bar cannot exceed 350mm. Considering only the weight of the bar determine (a) the allowable span of the beam from points A to B, aka the total length of the beam in meters, and (b) the radius of gyration of the bar in millimeters. Let d = 60mm, E = 210 GPa, v = 0.30. The specific weight of the steel is 77 kN/m³. Note: the maximum deflection of a beam due to its own weight is vmax = 5pL4 384EI' where p is the distributed load in N/m.
4. A round, horizontal, simply supported steel bar is subject to an axial compressive load, P = 5 kN, at each end acting at its centroid. Due to space constraints, the maximum deflection of the bar cannot exceed 350mm. Considering only the weight of the bar determine (a) the allowable span of the beam from points A to B, aka the total length of the beam in meters, and (b) the radius of gyration of the bar in millimeters. Let d = 60mm, E = 210 GPa, v = 0.30. The specific weight of the steel is 77 kN/m³. Note: the maximum deflection of a beam due to its own weight is vmax = 5pL4 384EI' where p is the distributed load in N/m.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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Transcribed Image Text:4. A round, horizontal, simply supported steel bar is subject to an axial compressive load, P = 5 kN, at
each end acting at its centroid. Due to space constraints, the maximum deflection of the bar cannot
exceed 350mm. Considering only the weight of the bar determine (a) the allowable span of the beam
from points A to B, aka the total length of the beam in meters, and (b) the radius of gyration of the bar
in millimeters. Let d = 60mm, E = 210 GPa, v = 0.30. The specific weight of the steel is 77 kN/m³.
5pL4
384EI'
Note: the maximum deflection of a beam due to its own weight is vmax =
where p is the
distributed load in N/m.
A
Extra credit: describe the
differences between strength,
stiffness and stability
L = ? m
P.
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