4. A right triangle has vertices (-2,5), (-2,–3) and (4,-3). Find its area and perimeter. does -8 .7 P 8tb+10 P= 24 .4 2 -1 -9-8-7-6-5-4 -3- 345 6 8 9 -4 -5 -6 -7 -8 -9 6++36-x2 lo0 Ex2 X=10 A = 24
4. A right triangle has vertices (-2,5), (-2,–3) and (4,-3). Find its area and perimeter. does -8 .7 P 8tb+10 P= 24 .4 2 -1 -9-8-7-6-5-4 -3- 345 6 8 9 -4 -5 -6 -7 -8 -9 6++36-x2 lo0 Ex2 X=10 A = 24
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
What’s the area of the Triangle

Transcribed Image Text:(x, y) → (, )
4. A right triangle has vertices (-2,5), (-2,–3)
and (4,-3). Find its area and perimeter.
does
8
-7
P8tb+10
-2
P=24
-9 -8 -7 -6 -5 -4 -3 --11
5 6
8 9
-4
-5
-6
-7
-8
64+36-x2
to0ニx2
X=10
A =
P =
24
6. Solve for x.
2(x-5) = 32
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