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- One mole of a gas obeys the Ideal Gas Law PV = 20T, where P is pressure, V is volume, and T is temperature. If the temperature T of the gas is increasing at the rate of 5 °C/s and if, when the temperature is 80 °C, the pressure P is 10N/m? and is decreasing at the rate of 2- find the m2 . s rate of change of the volume V with respect to time.Q1: 1. 3. Find the relative velocity of car A relative to в. Choose the correct answer 20 m/s 50 m/s A car is moving on a concave road as shown [30 m/s Find the reaction between the car and road mass of car = 900 kg and R = 50 m ( assume g = 10 m/s ) ( a =v/r) Select one: Select one: a. 50 m/s angle 45 a. 18000 kg b. 58.3 angle 30.9 b. 1800 kg c. 50 m/s angle 36.87 c. 18000 N d. 40 m/s angle 30 d. 16200 N 2. 4. A car initial velocity is 12 m/s moves with accn 3 Find the accn of the frictionless system shown. m/s Assume the pulleys are light and have no friction Assume g = 10 m/s" Find the its velocity after it moves a distance of 4kg 120 m 8 kg { laws you may use are 2 V,- V, = at , v. - v, = 2zas , s = v, t• 0.5 at } D1kg 5 kg Choose the correct answer Select one: a. 29.4 m/s Select one: b. 29.4 mm a. 1.579 m/s c. 23 m/s b. 2.22 m/s d. 21.9 m/s C. 2 m/s O d. 3 m/s1.75m 1.5 m 2.75m Given: G/0 Find: 2.25m Đ B h 2.0m • h = 0.35 meters Tension = 65 Newtons E 1.5m W Magnitude of internal shear force (Newtons) Axial Force AJO Bending moment V Shear force
- Pr1. A body of mass m = a vertical spring of spring constant k = 90 N/m. At t = 0 the body is displaced from its equilibri- um position downward by distance xo and it is given an initial velocity vo = 2,50 kg is hung on 13 cm 78 cm/s also directed downwards. a) Give the displacement x(t) of the body as a function of time. After how much time does the body pass through the equilibrium position first? b) Find the maximal displacement, speed and acceleration of the body during the motion. c) Find the total energy stored in the oscil- lation.Q1: A. A car moving at a velocity of 30 m/s accelerated at a rate of 0.5 m/s. Find the distance covered by the car in 25 seconds. В. Two forces act at an angle of 110° the bigger force is P-50 N as shown in the figure find the other force Q. B 110° 60 P=50 NEX- function of time t (in second ) is : The position s ( in meters ) of a moving body as s - 2t + 5t – 3 ; find : a a) The interval from t= 0 to t= 2 seconds . b) The body’s velocity at t=2 seconds . displacement and average velocity for the time
- 1.75m 1.5 m 2.75m Given: G/0 Find: 2.25m 6 o B 2.0m . h = 2.05 meters • Tension = 85 Newtons 26 1.5m W Magnitude of internal axial force (Newtons) Axial Force Bending moment V Shear force1- Find the velocity x and the position x as functions of the time t for a particle of mass m, which starts from rest at x =0 and t=0, subject to the following force functions: (a) F, = F. + ct (b) F = F, sin ct (c) F, = F, ed Where F, and c are positive constants.1.1 Find the rate at which water will flow in each pipe, ignoring the shock losses at P and entry to pipelines A and B. 1.2 Find the pressure at P. QUESTION 2 The diameter of an open-topped tank 1.5 m high increases uniformly from 4.2 m at the [2 base to 6 m at the top. Discharge from the base of the tank takes place through a 75mm diameter pipe which is 3 m in length. The pipe discharges the water to the atmosphere 1.5 m below the base of the tank. Initially, the tank is fully filled with water. Take f = 0.01. Find the time to empty the tank. QUESTION 3 Water must flow over a distance of 2 800 m from a large catchment dam to a turbine. [10 The water level in the catchment dam is 1 620 m above sea level and the turbine is situated 1 275 m above sea level. The efficiency of transmission is 65% and 300 kW must be transmitted from the pipeline to the turbine. Iff = 0.007, determine the number of 200 mm diameter pipelines, which must be laid in parallel, needed to transmit the required…
- A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest from a point 2 inches above the equilibrium position. Give the initial conditions. (Use g 32 ft/s? for the acceleration due to gravity.) x(0) X ft %3D x'(0) ft/s Find the equation of motion. x(t) X ft Need Help? Read It Watch ItQI/ Find the amount of force FB and FC so that the resultant of the external forces is zero. * Fc 50 N 50 N FB 30° 30° B 100 NY r = 0.35 10 NY -0.502-0.65-0.65- 50 NY 0.5+0.4- Dimensions in meters1.9 The volume flow rate through a pipe is given by Q=vA, where v is the average velocity and A is the cross-sectional area. Use volume-continuity to solve for the required area in pipe 3. Q1,in = 40 m/s 2.out = 20 m/s U3,out = 6 m/s Az = ?