4. A parallel-plate capacitor in air has a plate separation of 1.35 cm and a plate area of 35.0 cm². The plates are charged to a potential difference of 150 V and disconnected from the source. The capacitor is then immersed in distilled water. Assume the liquid is an insulator. Determine: a. the charge on the plates before and after immersion b. the capacitance and potential difference after immersion c. the change in energy of the capacitor after immersion

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only number 4 complete sol

Show your complete solution to each problem on a short bond paper.
Answers must be expressed in engineering notation (when the exponent of the base 10 multiplier
is not a multiple of 3, press ENG or SHIFT+ENG, whichever the case.)
Example: 0.06N or 6.0x10-2 N must be expressed to 60x10-3 N or 60mN
1. A capacitor is composed of 2 plates separated by a sheet of insulating material 2mm thick and of relative
permittivity 3. The distance between the plates is increased to allow the insertion of a second sheet of 3mm
thick and of relative permittvity ɛr . If the equivalent capacitance is one-half of the original capacitance, find
the value of ɛr.
2. In the given network, each capacitor has C = 4. 00 µF and
Vab = +28.0 V. Calculate the:
a. Total capacitance
b. Charge on each capacitor
c. Potential difference on each capacitor
3. A 20 µF capacitor is charged to 120 V and then disconnected from the power supply. If a second uncharged
capacitor with capacitance of 50 µF is connected across the first capacitor, what would be the resulting
voltage across their parallel combination?
4. A parallel-plate capacitor in air has a plate separation of 1.35 cm and a plate area of 35.0 cm². The plates
are charged to a potential difference of 150 V and disconnected from the source. The capacitor is then
immersed in distilled water. Assume the liquid is an insulator. Determine:
a. the charge on the plates before and after immersion
b. the capacitance and potential difference after immersion
c. the change in energy of the capacitor after immersion
5. Find the relative permittivity ɛr of the dielectric material present in a parallel-plate capacitor if:
A = 0.12 m², d = 80 µm, V =12 V, U =1 µJ
Transcribed Image Text:Show your complete solution to each problem on a short bond paper. Answers must be expressed in engineering notation (when the exponent of the base 10 multiplier is not a multiple of 3, press ENG or SHIFT+ENG, whichever the case.) Example: 0.06N or 6.0x10-2 N must be expressed to 60x10-3 N or 60mN 1. A capacitor is composed of 2 plates separated by a sheet of insulating material 2mm thick and of relative permittivity 3. The distance between the plates is increased to allow the insertion of a second sheet of 3mm thick and of relative permittvity ɛr . If the equivalent capacitance is one-half of the original capacitance, find the value of ɛr. 2. In the given network, each capacitor has C = 4. 00 µF and Vab = +28.0 V. Calculate the: a. Total capacitance b. Charge on each capacitor c. Potential difference on each capacitor 3. A 20 µF capacitor is charged to 120 V and then disconnected from the power supply. If a second uncharged capacitor with capacitance of 50 µF is connected across the first capacitor, what would be the resulting voltage across their parallel combination? 4. A parallel-plate capacitor in air has a plate separation of 1.35 cm and a plate area of 35.0 cm². The plates are charged to a potential difference of 150 V and disconnected from the source. The capacitor is then immersed in distilled water. Assume the liquid is an insulator. Determine: a. the charge on the plates before and after immersion b. the capacitance and potential difference after immersion c. the change in energy of the capacitor after immersion 5. Find the relative permittivity ɛr of the dielectric material present in a parallel-plate capacitor if: A = 0.12 m², d = 80 µm, V =12 V, U =1 µJ
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