**Gyroscope Flywheel Acceleration**A gyroscope flywheel with a radius of 2.83 cm is accelerated from rest at a rate of 14.2 rad/s² until its angular speed reaches 2760 revolutions per minute (rev/min).1. **Tangential Acceleration (a_t)**: *What is the tangential acceleration of a point on the rim of the flywheel during this spin-up process?*2. **Radial Acceleration (a_r)**: *What is the radial acceleration of this point when the flywheel is spinning at full speed?*3. **Distance Moved on the Rim**: *Through what distance does a point on the rim move during the spin-up?*In solving these questions, one should:1. Convert angular speed from revolutions per minute to radians per second if necessary.2. Use the formulas for tangential and radial acceleration.3. Calculate the distance using the relation between angular displacement and the radius of the flywheel.These principles and calculations help in understanding the dynamics of rotating bodies and the effects of their acceleration.

Given, r = 2.83 cm = 0.0283 m α=14.2 rad/s2\alpha = 14.2 \ rad/s^2 f0=0 rev/min ffinal=2760 rev/min…

Answered: 4. A gyroscope flywheel of radius 2.83…

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