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4. (a) Define the electromotive force and explain the physical mechanism of the electromotive force source. (b) One circuit has constructed by electromotive force source which has ɛ = 5V and inner resistivity r = values of R1 powers dissipated in R1, R2 and r. 1N. Two serial connected resistances which have 5N placed in that circuit. Calculate the IN and R2

4. (a) Define the electromotive force and explain the physical mechanism of the electromotive force source. (b) One circuit has constructed by electromotive force source which has ɛ = 5V and inner resistivity r = values of R1 powers dissipated in R1, R2 and r. 1N. Two serial connected resistances which have 5N placed in that circuit. Calculate the IN and R2

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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it was an old question on exam, and I want know jow I can solve this question.

4. (a) Define the electromotive force and explain the physical mechanism of the electromotive force source. (b) One circuit has constructed by electromotive force source which has ɛ = 5V and inner resistivity r = 12. Two serial connected resistances which have values of R1 1N and R2 5N placed in that circuit. Calculate the %3D powers dissipated in R1, R2 and r. • Gauss's law: qin €0 Here E is the electric field vector, da is the surface element vector, qin is the total charge enclosed by the Gaussian surface, €o is the electric constant. The integral is taken over the closed Gaussian surface. • Electric potential at point P due to charge q is given by V = k2. 1 q 4T€0 r where r is the distance between the point P and the charge q. k = 9 x 10°NM2/C², eo = 8.854 × 10-12C²/(Nm²). • The power is defined by P = VI = I²R= V² /R
Transcribed Image Text:4. (a) Define the electromotive force and explain the physical mechanism of the electromotive force source. (b) One circuit has constructed by electromotive force source which has ɛ = 5V and inner resistivity r = 12. Two serial connected resistances which have values of R1 1N and R2 5N placed in that circuit. Calculate the %3D powers dissipated in R1, R2 and r. • Gauss's law: qin €0 Here E is the electric field vector, da is the surface element vector, qin is the total charge enclosed by the Gaussian surface, €o is the electric constant. The integral is taken over the closed Gaussian surface. • Electric potential at point P due to charge q is given by V = k2. 1 q 4T€0 r where r is the distance between the point P and the charge q. k = 9 x 10°NM2/C², eo = 8.854 × 10-12C²/(Nm²). • The power is defined by P = VI = I²R= V² /R
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