4. A cable with supports at the same elevation is being designed to carry a uniformly distributed load of 1.50 kN along the horizontal. The sag of the cable at midspan is 4 m. The maximum tension in the cable is limited to 15 kN. a) Determine the maximum horizontal force of the lowest part of the cable. b) Compute the maximum allowable span for the cable. c) Find the required length of the cable. L A d=4m 1.50 KN/m

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