Hi, I need help with number 4, thank you ### Problem StatementA biker is accelerating when she applies the brakes and then speeds up again. The net horizontal force is shown in the graph. Assume she moves in a straight line and the mass of the biker and bike is 80 kg. The biker was moving at 8 m/s at \( t = 0 \). How fast is she moving at \( t = 20 \, \text{s} \)?### Graph DescriptionThe graph represents the net horizontal force applied on the biker over time. - On the y-axis, the net x-Force is measured in Newtons (N), with values ranging from -40 N to 40 N.- On the x-axis, time is measured in seconds (sec), ranging from 0 to 20 seconds.#### Graph Details:1. From \( t = 0 \, \text{s} \) to \( t = 8 \, \text{s} \), the net x-Force is constant at 20 N.2. At \( t = 8 \, \text{s} \), the net x-Force drops sharply to -20 N and remains constant until \( t = 12 \, \text{s} \).3. From \( t = 12 \, \text{s} \) to \( t = 16 \, \text{s} \), the net x-Force increases linearly from -20 N to 10 N.4. From \( t = 16 \, \text{s} \) to \( t = 20 \, \text{s} \), the net x-Force remains constant at 10 N.### Solution Steps1. **Calculation of Acceleration and Velocity:** - Use Newton's second law, \( F = ma \), to find acceleration for each time interval. 2. **First Interval (0 to 8 seconds):** - Force \( F = 20 \, \text{N} \) - Mass \( m = 80 \, \text{kg} \) - Acceleration \( a = \frac{F}{m} = \frac{20}{80} = 0.25 \, \text{m/s}^2 \) Velocity at \( t = 8 \, \text{s} \): \[ V_1 = V_0 + at = 8 + 0.25 \times

Name: Hi, I need help with number 4, thank you ### Problem StatementA biker
Uploaded: 2024-03-20T06:57:57.000Z
Channel: Bartleby
Description: Hi, I need help with number 4, thank you ### Problem StatementA biker is accelerating when she applies the brakes and then speeds up again. The net horizontal force is shown in the graph. Assume she moves in a straight line and the mass of the biker