4. A 50 kg man stands on the middle rung of a 50 kg ladder as shown. Assuming the floor and wall are perfectly smooth and that slipping is prevented by a string DE. a. Find the reaction at B. b. C. Find the reaction at A. Find the tension in string DE. 12m 150 kg 50 kg 6m 30% B E
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- 4. The system can freely rotate about the pivot if it is not balanced. The bar is uniform and its mass (M) is 150 g. The other hanging masses are shown in the Figure. Find the value of 'm' for the system to be in equilibrium. 40 cm 30 cm - 30 cm pivot o M= 150 g 160 g 140 g4. A machine part consists of a thin, uniform 4.00-kg bar that is 1.50 m long, hinged perpendicular to a similar vertical bar of mass 3.00 kg and length 1.80 m. The longer bar has a small but dense 2.00-kg ball at one end (see figure). a. Find the position of the center of mass of the top bar relative to the hinge. Write out its x- and y-components. b. Find the position of the center of mass of the vertical bar relative to the hinge. Write out its x- and y-components. c. Find the center of mass of the ball relative to the hinge. Write out its x- and y-components. d. Use your answers to parts (a)-(c) to find the center of mass of the entire machine part relative to the hinge. Write out its x- and y-components. -1.50 m- 4.00 kg Hinge 3.00 kg 1.80 m 2.00 kgA horizontal meter stick supported at the 50-cm mark has a mass of 0.60 kg hanging from it at the 15- cm mark and a 0.40 kg mass hanging from it at the 70-cm mark. Determine the position on the meter stick at which one would hang a third mass of 0.50 kg to keep the meter stick balanced. A. 26 cm mark B. 56 cm mark OC. 58 cm mark D. 76 cm mark E. 84 cm mark
- 3. Two parents are doing some home improvement and their baby falls asleep on a board they are moving (parents of the year). The board is 3.80 m long and the baby is 0.45 m from one end of the board. The parents are holding the board from either edge. The board has a mass of 3.1 kg and the baby has a mass of 10.2 kg. Draw a free-body diagram and label each force and distances. Also choose and mark a pivot point for your board on the drawing. а. b. Write out E F and Ei for your diagram. Don't solve yet. For each of the torques you wrote down in part b, use the right-hand rule to say whether the direction of torque is into the page or out of the page. с.A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 5.04 g coins stacked over the 18.2 cm mark, the stick is found to balance at the 41.8 cm mark. What is the mass of the meter stick? Number i UnitsA block is sliding down a ramp at a constant velocity. Which one of the following statements is true? a. The block is not in equilibrium because the net torque on the block is not equal to zero N.m b. The block is in equilibrium, but it is not in static equilibrium. c. The block is not in equilibrium because the net forces on the block are not equal to zero newtons. d. The block is in static equilibrium. e. The block is not in equilibrium because the linear momentum of the block is not equal to zero kg.m/s.
- A 4-m long, 150-kg steel beam is attached to a wall with one end connected to a hinge that allows the beam to rotate up and down. The other end of the beam is held in a horizontal position with a cable that makes a 27° angle with the beam and is attached to the wall (see (Figure 1)). a.What is the tension force that keeps this beam in static equilibrium? b. A mass of 75 kg is hung from the beam 3 meters away from the hinge (see (Figure 2)). Now what is the tension force that keeps this beam in static equilibrium? c.What is the vertical component of the force that the hinge exerts on the beam?With regard to mechanical equilibrium with respect to forces and torques: A. Net Forces and Net Torques cannot be positive. B. The Net force and Net Torque vanish for at least one system components. C. Net forces or net torques vanish for all system components. D. Net forces and net torques vanish for all system components.A uniform meterstick is supported at the 50 cm mark. A 25N weight is placed at the 10 cm mark. Where should a 200N weight be placed for the meter stick to be in equilibrium? a.1.25 cm mark b. 45.5 cm mark c. 51.3 cm mark d. 80.0 cm mark
- A solid rod of mass 200 g and length L = 0.50 m is suspended using two strings with equal tensions T₁ and T2 as shown below. How far from the left end of the rod should you place a 50 g weight while maintaining the the rod horizontal? T2 A. L/2 B. L/3 C. L/6 OD. 2L/3 OE. 5L/6 T₁4. A meter stick has a pivot that is located at (35 cm). On this meter stick weplace 200 g @ 20 cm, 200 g @ 25 cm, 350 g @70 cm and 100 g @80 cm.The meter stick has a mass of 150 g. a. How much mass needs to be placed at 55 cm in order to balance themeter stick.__________________________ b. Where will you put 500 g in order to balance the meterstick?___________________________________ If you could clearly circle the answers I need, that would be great! Thanks!a. A 1200-N uniform boom of length 2.00 m is supported by a cable, as shown in the figure. The boom is pivoted at the bottom, and a 2000-N weight hands from its top. Find the tension in the cable and the components of the reaction force exerted on the boom by the floor. For the next two parts you can assume that the 2000-N weight is concentrated at the top end of the boom. b. Determine the total moment of inertia of the boom/weight system around the pivot point. c. The cable now breaks, and the boom pivots until the right end hits the floor. Determine the velocity of the right end at the instant before it hits the floor.