**Problem 4: Collision of Two Blocks**A 5.0 kg block moving to the right at 12.0 m/sec collides with a 4.0 kg block moving to the right at 2 m/sec. If the 4.0 kg block moves to the right at 10 m/sec after the collision, what will be the speed of the 5.0 kg block? How much energy was lost during the collision?---To solve this problem, you need to apply the principle of conservation of momentum and calculate the kinetic energy before and after the collision.**Conservation of Momentum:**- Calculate the initial total momentum: \[ \text{Initial momentum} = (5.0\, \text{kg} \times 12.0\, \text{m/s}) + (4.0\, \text{kg} \times 2.0\, \text{m/s}) \]- Use the final velocity of the 4.0 kg block and the conservation of momentum to find the speed of the 5.0 kg block after the collision.**Kinetic Energy:**- Find the initial kinetic energy of both blocks.- Find the final kinetic energy of both blocks and compare it to the initial kinetic energy to determine the energy lost during the collision.

Name: **Problem 4: Collision of Two Blocks**A 5.0 kg block moving to the ri
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Description: **Problem 4: Collision of Two Blocks**A 5.0 kg block moving to the right at 12.0 m/sec collides with a 4.0 kg block moving to the right at 2 m/sec. If the 4.0 kg block moves to the right at 10 m/sec after the collision, what will be the speed of the

The mass of first block is m1 = 5.0 kg. The mass of second block is m2 = 4.0 kg. Assume the velocity…

Answered: 4. A 5.0 kg block moving to the right…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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**Problem 4: Collision of Two Blocks**

A 5.0 kg block moving to the right at 12.0 m/sec collides with a 4.0 kg block moving to the right at 2 m/sec. If the 4.0 kg block moves to the right at 10 m/sec after the collision, what will be the speed of the 5.0 kg block? How much energy was lost during the collision?

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To solve this problem, you need to apply the principle of conservation of momentum and calculate the kinetic energy before and after the collision.

**Conservation of Momentum:**

- Calculate the initial total momentum:

\[
\text{Initial momentum} = (5.0\, \text{kg} \times 12.0\, \text{m/s}) + (4.0\, \text{kg} \times 2.0\, \text{m/s})
\]

- Use the final velocity of the 4.0 kg block and the conservation of momentum to find the speed of the 5.0 kg block after the collision.

**Kinetic Energy:**

- Find the initial kinetic energy of both blocks.

- Find the final kinetic energy of both blocks and compare it to the initial kinetic energy to determine the energy lost during the collision.

Expert Solution

Step 1

The mass of first block is m₁ = 5.0 kg.

The mass of second block is m₂ = 4.0 kg.

Assume the velocity towards right as positive.

The initial velocity of the first block is u₁ = + 12 m/s. (Before Collision)

The initial velocity of the second block is u₂ = + 2 m/s. (Before Collision)

The final velocity of the second block is v₂ = 10 m/s. (After Collision)

Assume the final velocity of the first block is denoted by v₁. (After Collision)

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