4. A 10.00-mL sample of a vinegar solution is titrated with a 0.178N NaOH solution. It requires 48.12 mL of the base solution to turn the solution in flask light pink. What is the amount of equivalent of base in the 48.12-mL portion? What is the amount of equivalent of the acid in the vinegar sample? What is the normality of the vinegar solution?
4. A 10.00-mL sample of a vinegar solution is titrated with a 0.178N NaOH solution. It requires 48.12 mL of the base solution to turn the solution in flask light pink. What is the amount of equivalent of base in the 48.12-mL portion? What is the amount of equivalent of the acid in the vinegar sample? What is the normality of the vinegar solution?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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4. A 10.00-mL sample of a vinegar solution is titrated with a 0.178N NaOH solution. It requires 48.12 mL of the base solution to turn the solution in flask light pink.
What is the amount of equivalent of base in the 48.12-mL portion? What is the amount of equivalent of the acid in the vinegar sample? What is the normality of the vinegar solution?
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