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4. 6x3 2 7x2 + 3x

4. 6x3 2 7x2 + 3x

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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4.00 :4Gil ll21%O 11:16 KB/S 2 Chapte BEIE Anwer You on Page 30 Francis Adrra +34 ADVANCED ALGEBRA Exercise 1.2 Non-linear Inequality Solve the following inequality statements. Show your answer in simplified inequality notation, interval notation and line graph. Check the solution set by assuming value of x in every interval. set 1. x2 – x – 12 < 0 13. 3x2 - 7x + 2 20 2. x2 < 15 + 2x 14. 9x2 – 4 <0 ue. 3. (2x + 3)(3x – 5) > 0 15. 3x2 - x < 2 4. 6x3 2 7x2 + 3x 2x+3 < 1 x-1 16. 5. (x – 1)(x + 3)(x – 4) > 0 4х-1 + 4 <0 2x-1 17. x + 6 6. X-4 xマ-5x+4 > 0 18. x+1 7. x + 1 2x-1 2x x+3 2 - 7x 19. -(x-3) 20 2(х-3) 8. <4 5- 4x 6. 9. >x + 1 20. 3x2 – 4x – 4 2 0 3x-4 2x-7 10. 12 21. x2 - 6x + 8 3x-4 6x-7 11. 4x2 – 12x <0 2 22. x+4 3x-2 12. x(x+8) < -15 Inequality Page 31
Transcribed Image Text:4.00 :4Gil ll21%O 11:16 KB/S 2 Chapte BEIE Anwer You on Page 30 Francis Adrra +34 ADVANCED ALGEBRA Exercise 1.2 Non-linear Inequality Solve the following inequality statements. Show your answer in simplified inequality notation, interval notation and line graph. Check the solution set by assuming value of x in every interval. set 1. x2 – x – 12 < 0 13. 3x2 - 7x + 2 20 2. x2 < 15 + 2x 14. 9x2 – 4 <0 ue. 3. (2x + 3)(3x – 5) > 0 15. 3x2 - x < 2 4. 6x3 2 7x2 + 3x 2x+3 < 1 x-1 16. 5. (x – 1)(x + 3)(x – 4) > 0 4х-1 + 4 <0 2x-1 17. x + 6 6. X-4 xマ-5x+4 > 0 18. x+1 7. x + 1 2x-1 2x x+3 2 - 7x 19. -(x-3) 20 2(х-3) 8. <4 5- 4x 6. 9. >x + 1 20. 3x2 – 4x – 4 2 0 3x-4 2x-7 10. 12 21. x2 - 6x + 8 3x-4 6x-7 11. 4x2 – 12x <0 2 22. x+4 3x-2 12. x(x+8) < -15 Inequality Page 31
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