4. (13.49) If the pressure in a gas is tripled while its volume is held constant, by what factor does rms change?

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Chapter13: Temperature, Kinetic Theory, And The Gas Laws
Section: Chapter Questions
Problem 34PE: A high—pressure gas cylinder contains 50.13L of toxic gas at a pressure of 1.40107N/m2 and a...
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**Problem Statement:**

4. **(13.49)** If the pressure in a gas is tripled while its volume is held constant, by what factor does \(v_{\text{rms}}\) change?

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### Explanation

Consider the given problem as part of a larger discussion on the relationships between pressure, volume, temperature, and the root mean square speed (\(v_{\text{rms}}\)) of gas molecules. According to the ideal gas law, the relationship between pressure (P), volume (V), and temperature (T) is given by:

\[ PV = nRT \]

where \( n \) is the number of moles of the gas, and \( R \) is the universal gas constant.

The root mean square speed (\(v_{\text{rms}}\)) of the gas molecules is related to the temperature by the equation:

\[ v_{\text{rms}} = \sqrt{\frac{3kT}{m}} \]

where \( k \) is the Boltzmann constant and \( m \) is the mass of a gas molecule. 

Given that the volume is constant and the pressure is tripled, we can use the ideal gas law to determine how the temperature changes:

Since \( V \) is constant, from \( PV = nRT \):

\[ P_1 V = nR T_1 \]

After tripling the pressure:

\[ P_2 = 3P_1 \]

\[ P_2 V = nR T_2 \]

Substituting \( P_2 \) as \( 3P_1 \):

\[ 3P_1 V = nR T_2 \]

Since \( P_1 V = nR T_1 \), we can write:

\[ T_2 = 3T_1 \]

Thus, the temperature is tripled. Now, considering the \(v_{\text{rms}}\) equation:

\[ v_{\text{rms}} \propto \sqrt{T} \]

When the temperature is tripled:

\[ v_{\text{rms}_2} = \sqrt{3T_1} = \sqrt{3} \times \sqrt{T_1} \]

Therefore, when the pressure in the gas is tripled while its volume is held constant, the root mean square speed (\(v_{\text{rms}}\)) changes by a factor of \( \sqrt{3
Transcribed Image Text:**Problem Statement:** 4. **(13.49)** If the pressure in a gas is tripled while its volume is held constant, by what factor does \(v_{\text{rms}}\) change? --- ### Explanation Consider the given problem as part of a larger discussion on the relationships between pressure, volume, temperature, and the root mean square speed (\(v_{\text{rms}}\)) of gas molecules. According to the ideal gas law, the relationship between pressure (P), volume (V), and temperature (T) is given by: \[ PV = nRT \] where \( n \) is the number of moles of the gas, and \( R \) is the universal gas constant. The root mean square speed (\(v_{\text{rms}}\)) of the gas molecules is related to the temperature by the equation: \[ v_{\text{rms}} = \sqrt{\frac{3kT}{m}} \] where \( k \) is the Boltzmann constant and \( m \) is the mass of a gas molecule. Given that the volume is constant and the pressure is tripled, we can use the ideal gas law to determine how the temperature changes: Since \( V \) is constant, from \( PV = nRT \): \[ P_1 V = nR T_1 \] After tripling the pressure: \[ P_2 = 3P_1 \] \[ P_2 V = nR T_2 \] Substituting \( P_2 \) as \( 3P_1 \): \[ 3P_1 V = nR T_2 \] Since \( P_1 V = nR T_1 \), we can write: \[ T_2 = 3T_1 \] Thus, the temperature is tripled. Now, considering the \(v_{\text{rms}}\) equation: \[ v_{\text{rms}} \propto \sqrt{T} \] When the temperature is tripled: \[ v_{\text{rms}_2} = \sqrt{3T_1} = \sqrt{3} \times \sqrt{T_1} \] Therefore, when the pressure in the gas is tripled while its volume is held constant, the root mean square speed (\(v_{\text{rms}}\)) changes by a factor of \( \sqrt{3
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