4 y mg(1.2) = 0.5mv → v = V2.4g = 4.8522 (m/s) 1 (2) Collision at position 2 1.2 m Before collision 3 4 V =-vj = -v(- ên 3 = vê, + vê, • After collision, assume 5 3 v, = v"ê, + v{ ê̟ 4 2.

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