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(4) V2T 54+을 e-5 er е 12.5 %3D

(4) V2T 54+을 e-5 er е 12.5 %3D

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Mathematical Series and Representation This section provides exercises to understand mathematical functions and series representations. #### Exercises Evaluate the following expressions: 1. \[ \sqrt{2\pi} \; \frac{11^{\frac{1}{2}}}{e^{11} \; e^{\frac{1}{12 \cdot 11}}} = \begin{array}{|c|c|c|c|c|c|c|c|c|} \hline & & & & & & & & \\ \hline \end{array} \text{{ ...}} \] 2. \[ \sqrt{2\pi} \; \frac{12^{\frac{1}{2}}}{e^{12} \; e^{\frac{1}{12 \cdot 12}}} = \begin{array}{|c|c|c|c|c|c|c|c|c|c|} \hline & & & & & & & & & \\ \hline \end{array} \text{{ ...}} \] 3. \[ \sqrt{2\pi} \; \frac{13^{\frac{1}{2}}}{e^{13} \; e^{\frac{1}{12 \cdot 13}}} = \begin{array}{|c|c|c|c|c|c|c|c|c|c|c|} \hline & & & & & & & \ast & & & \\ \hline \end{array} \text{{ ...}} \] 4. \[ \sqrt{2\pi} \; \frac{14^{\frac{1}{2}}}{e^{14} \; e^{\frac{1}{12 \cdot 14}}} = \begin{array}{|c|c|c|c|c|c|c|c|c|c|c|c|} \hline & & & & & & \ast & \ast & \\ \hline \end{array} \text{{ ...}} \] 5. \[ \sqrt{2\pi} \; \frac{15^{\frac{1}{2}}}{
Transcribed Image Text:### Mathematical Series and Representation This section provides exercises to understand mathematical functions and series representations. #### Exercises Evaluate the following expressions: 1. \[ \sqrt{2\pi} \; \frac{11^{\frac{1}{2}}}{e^{11} \; e^{\frac{1}{12 \cdot 11}}} = \begin{array}{|c|c|c|c|c|c|c|c|c|} \hline & & & & & & & & \\ \hline \end{array} \text{{ ...}} \] 2. \[ \sqrt{2\pi} \; \frac{12^{\frac{1}{2}}}{e^{12} \; e^{\frac{1}{12 \cdot 12}}} = \begin{array}{|c|c|c|c|c|c|c|c|c|c|} \hline & & & & & & & & & \\ \hline \end{array} \text{{ ...}} \] 3. \[ \sqrt{2\pi} \; \frac{13^{\frac{1}{2}}}{e^{13} \; e^{\frac{1}{12 \cdot 13}}} = \begin{array}{|c|c|c|c|c|c|c|c|c|c|c|} \hline & & & & & & & \ast & & & \\ \hline \end{array} \text{{ ...}} \] 4. \[ \sqrt{2\pi} \; \frac{14^{\frac{1}{2}}}{e^{14} \; e^{\frac{1}{12 \cdot 14}}} = \begin{array}{|c|c|c|c|c|c|c|c|c|c|c|c|} \hline & & & & & & \ast & \ast & \\ \hline \end{array} \text{{ ...}} \] 5. \[ \sqrt{2\pi} \; \frac{15^{\frac{1}{2}}}{
**Problem.** In each line, give an approximate value in decimals using a calculator. 1. \(\sqrt{2\pi} \cdot 2^{1 + \frac{1}{2}} \cdot e^{-2} \cdot e^{\frac{1}{12 \cdot 2}} =\) \(\boxed{1} \boxed{0} \boxed{0} \boxed{0} \boxed{3} \cdots\) 2. \(\sqrt{2\pi} \cdot 3^{2 + \frac{1}{2}} \cdot e^{-3} \cdot e^{\frac{1}{12 \cdot 3}} =\) \(\boxed{2} \boxed{0} \boxed{0} \boxed{0} \boxed{1} \cdots\) 3. \(\sqrt{2\pi} \cdot 4^{3 + \frac{1}{2}} \cdot e^{-4} \cdot e^{\frac{1}{12 \cdot 4}} =\) \(\boxed{6} \boxed{0} \boxed{0} \boxed{0} \boxed{2} \cdots\) 4. \(\sqrt{2\pi} \cdot 5^{4 + \frac{1}{2}} \cdot e^{-5} \cdot e^{\frac{1}{12 \cdot 5}} =\) \(\boxed{} \boxed{} \boxed{} \boxed{} \boxed{} \cdots\) 5. \(\sqrt{2\pi} \cdot 6^{5 + \frac{1}{2}} \cdot e^{-6} \cdot e^{\frac{1}{12 \cdot 6}} =\) \(\boxed{} \boxed{} \boxed{} \boxed{} \boxed{} \cdots\) 6. \(\sqrt{2\pi} \cdot 7^{6 + \frac{1}{2}} \cdot e^{-7} \cdot e^{\frac{1}{12 \cdot 7}} =\) \(\boxed{} \boxed{} \boxed{} \boxed{} \boxed{} \cdots\) 7. \(\sqrt{2\pi} \cdot
Transcribed Image Text:**Problem.** In each line, give an approximate value in decimals using a calculator. 1. \(\sqrt{2\pi} \cdot 2^{1 + \frac{1}{2}} \cdot e^{-2} \cdot e^{\frac{1}{12 \cdot 2}} =\) \(\boxed{1} \boxed{0} \boxed{0} \boxed{0} \boxed{3} \cdots\) 2. \(\sqrt{2\pi} \cdot 3^{2 + \frac{1}{2}} \cdot e^{-3} \cdot e^{\frac{1}{12 \cdot 3}} =\) \(\boxed{2} \boxed{0} \boxed{0} \boxed{0} \boxed{1} \cdots\) 3. \(\sqrt{2\pi} \cdot 4^{3 + \frac{1}{2}} \cdot e^{-4} \cdot e^{\frac{1}{12 \cdot 4}} =\) \(\boxed{6} \boxed{0} \boxed{0} \boxed{0} \boxed{2} \cdots\) 4. \(\sqrt{2\pi} \cdot 5^{4 + \frac{1}{2}} \cdot e^{-5} \cdot e^{\frac{1}{12 \cdot 5}} =\) \(\boxed{} \boxed{} \boxed{} \boxed{} \boxed{} \cdots\) 5. \(\sqrt{2\pi} \cdot 6^{5 + \frac{1}{2}} \cdot e^{-6} \cdot e^{\frac{1}{12 \cdot 6}} =\) \(\boxed{} \boxed{} \boxed{} \boxed{} \boxed{} \cdots\) 6. \(\sqrt{2\pi} \cdot 7^{6 + \frac{1}{2}} \cdot e^{-7} \cdot e^{\frac{1}{12 \cdot 7}} =\) \(\boxed{} \boxed{} \boxed{} \boxed{} \boxed{} \cdots\) 7. \(\sqrt{2\pi} \cdot
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