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4) The enantiomer of L-tartaric acid is D-tartaric acid. Draw the structure of D-tartaric acid, and label each chiral carbon as R or S.

4) The enantiomer of L-tartaric acid is D-tartaric acid. Draw the structure of D-tartaric acid, and label each chiral carbon as R or S.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Transcription for Educational Use #### Questions 3) Why does the (R,R)-1,2-diaminocyclohexane form a solid complex with L-tartaric acid while the (S,S)-1,2-diaminocyclohexane does not? (*Hint: redraw the reaction scheme from the bottom of page 1 of this lab and use this in your explanation*). 4) The enantiomer of L-tartaric acid is D-tartaric acid. Draw the structure of D-tartaric acid, and label each chiral carbon as R or S. 5) Which enantiomer of *trans*-1,2-diaminocyclohexane would you expect that the D-tartaric acid would form a solid complex with? Explain. #### Diagram Explanation The diagram depicts a chemical reaction involving (R,R)-1,2-diaminocyclohexane and tartaric acid. The structures in the diagram are as follows: - **Left Side**: - Shows (R,R)-1,2-diaminocyclohexane with two amine groups (NH₂) on a cyclohexane ring. - Tartaric acid structure with two hydroxyl groups (OH) and two carboxylic acid groups (COOH). - **Reaction Arrow**: - Indicates the formation of products on the right side. - **Right Side**: - Two complex structures are formed, each with tartaric acid coordinating with the 1,2-diaminocyclohexane. - The product labeled (s) and (aq) suggests a solid complex and an aqueous solution form, respectively. The diagram illustrates the stereochemical interactions required for the formation of a solid complex.
Transcribed Image Text:### Transcription for Educational Use #### Questions 3) Why does the (R,R)-1,2-diaminocyclohexane form a solid complex with L-tartaric acid while the (S,S)-1,2-diaminocyclohexane does not? (*Hint: redraw the reaction scheme from the bottom of page 1 of this lab and use this in your explanation*). 4) The enantiomer of L-tartaric acid is D-tartaric acid. Draw the structure of D-tartaric acid, and label each chiral carbon as R or S. 5) Which enantiomer of *trans*-1,2-diaminocyclohexane would you expect that the D-tartaric acid would form a solid complex with? Explain. #### Diagram Explanation The diagram depicts a chemical reaction involving (R,R)-1,2-diaminocyclohexane and tartaric acid. The structures in the diagram are as follows: - **Left Side**: - Shows (R,R)-1,2-diaminocyclohexane with two amine groups (NH₂) on a cyclohexane ring. - Tartaric acid structure with two hydroxyl groups (OH) and two carboxylic acid groups (COOH). - **Reaction Arrow**: - Indicates the formation of products on the right side. - **Right Side**: - Two complex structures are formed, each with tartaric acid coordinating with the 1,2-diaminocyclohexane. - The product labeled (s) and (aq) suggests a solid complex and an aqueous solution form, respectively. The diagram illustrates the stereochemical interactions required for the formation of a solid complex.
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