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4) The 2 lb piece of putty is dropped 6 ft onto the 18 lb block initially at rest on the two springs, each with k = 3 lb/in. Calculate the additional deflection of the springs due to the impact of the putty, which adheres to the block upon contact. 2 lb 6' 18 lb δ k = 3 lb/in. FULL CREDIT AWARDED ONLY FOR CORRECT FBD & KFD INCLUDED IN SOLUTION ANS. 8=2.56 inches

4) The 2 lb piece of putty is dropped 6 ft onto the 18 lb block initially at rest on the two springs, each with k = 3 lb/in. Calculate the additional deflection of the springs due to the impact of the putty, which adheres to the block upon contact. 2 lb 6' 18 lb δ k = 3 lb/in. FULL CREDIT AWARDED ONLY FOR CORRECT FBD & KFD INCLUDED IN SOLUTION ANS. 8=2.56 inches

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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This is not a quiz question. It is part of a review packet. Free Body Diagram and Kinetic Free Diagram needed. 

4) The 2 lb piece of putty is dropped 6 ft onto the 18 lb block initially at rest on the two springs, each with k = 3 lb/in. Calculate the additional deflection of the springs due to the impact of the putty, which adheres to the block upon contact. 2 lb 6' 18 lb δ k = 3 lb/in. FULL CREDIT AWARDED ONLY FOR CORRECT FBD & KFD INCLUDED IN SOLUTION ANS. 8=2.56 inches
Transcribed Image Text:4) The 2 lb piece of putty is dropped 6 ft onto the 18 lb block initially at rest on the two springs, each with k = 3 lb/in. Calculate the additional deflection of the springs due to the impact of the putty, which adheres to the block upon contact. 2 lb 6' 18 lb δ k = 3 lb/in. FULL CREDIT AWARDED ONLY FOR CORRECT FBD & KFD INCLUDED IN SOLUTION ANS. 8=2.56 inches
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