(4 points) Suppose the position (in feet) of an object moving horizontally at time t (in seconds) is s(t) = 2t3- 21t2 + 60t for 00 corresponding to positions to the right of %3D s = 0. a). Find the velocity function on the interval 0
(4 points) Suppose the position (in feet) of an object moving horizontally at time t (in seconds) is s(t) = 2t3- 21t2 + 60t for 00 corresponding to positions to the right of %3D s = 0. a). Find the velocity function on the interval 0
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:(4 points) Suppose the position (in feet) of an object moving horizontally at time t (in seconds)
is s(t) = 2t3- 21t2 + 60t for 0<t<7, with s>0 corresponding to positions to the right of
s = 0.
a). Find the velocity function on the interval 0 <t<7, and determine when the object is
stationary, moving to the left, and moving to the right.
b). Find the position(s) of the object when its velocity is zero, mark the position(s) on the
graph. Try to explain the position(s) related to part (a).
c). Find the acceleration function on the interval 0 <t < 7. On what intervals is the speed
increasing?
s(t), the velocity function v(t) = s'(t), and the accelera-
d). Graph the position function s =
tion function a(t) = v'(t) s"(t). (Graph all of them on one xy-coordinate plane.)
%3D
s(t) on a horizontal line (y 0,0<IS 77), indicating all interesting
e). Optional: Draw r =
points (t, s(t)) mentioned in (a)- (c).
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