4) Mean water levels of 29 years of flood events are measured in the Sakarya River. Observed water levels (in cm)are given below:547, 709, 833, 714, 522, 613, 656, 562, 482, 757, 683, 587, 501, 601, 805, 701, 463, 635, 912, 738, 766, 645, 729,434, 579, 535, 789, 1031, 450,a) Show that the observed values fit the log-normal distribution. Explain the reasons.b) Find the values for 50,100, 250, 500 and 1000-year periods by using the frequency factor method.

Given: 547 709 833 714 522 613 656 562 482 757 683 587 501 601 805…

Answered: 4) Mean water levels of 29 years of…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Data on pull-off force (pounds) for connectors used in an automobile engine application are as follows: 79.3, 75.1, 78.2, 74.1, 73.9, 75.0, 77.6, 77.3, 73.8, 74.6, 75.5, 74.0, 74.7, 75.9, 72.9, 73.8, 74.2, 78.1, 75.4, 76.3, 75.3, 76.2, 74.9, 78.0, 75.1, 76.8. d) Calculate a point estimate of the proportion of all connectors in the population whose pull-off force is less than 73 pounds e) Construct a 95% one-sided upper confidence bound for the proportion in part(d). f) Construct a 95% two-sided confidence interval on the mean pull-off force. g) Construct a 95% lower confidence bound on the mean pull-off force. Compare this bound with the lower bound of the two-sided confidence interval and discuss why they are different.
Assume critical reading scores for a standardized test are distributed as N(550,50). Complete parts (a) through (d) below.
b) In a company having 80 employees, 60 earn Rs. 3 per hour and 20 earn Rs. 2 per hour. Determine the mean earning per hour
1. . Construct a relative frequency and percentage frequency distribution tables. Thirty AAA lithium ion batteries were tested to determine how long they would last. The results, to the nearest minute, were recorded as follows: 423, 369, 387, 411, 393, 394, 371, 377, 389, 409, 392, 408, 431, 401, 363, 391, 405, 382, 400,381, 399, 415, 428, 422, 396, 372, 410, 419, 386, 390 Use the data above to make a table giving the relative frequency and percentage frequencyof each interval of battery life.
Set up a calculation used to determine how many possible samples of 8,315 respondents are possible from this population of 22 million people using theoretical sampling.
1-) For the following data, please compute: X= [1,2. 2, 3, 3, 3, 4, 4, 4, 4, 5, 5,5, 6, 6, 6, 7, 7, ,8,9] A) Arithmetic mean, mode, median, and standard deviation. B) plot the histogram or ogive 2-) Complete the frequency distribution table: Classes descending cumulative frequency Class centre Frequency 11-20 21-30 31-40 41-50 51-60 15.5 25.5 35.5 45.5 4 20 43 32 100 55.5 16 50 10 3-) a - From the values: 63, 60,74, 91, 93, 35, 72, 71, 84, 80 Find: 1- The Range 2- The number of classes 3- The length of class b- Find ou: which is more dispersion variable (X) or variable (Y), if the Arithmetic Mean and the Standard Deviation of them are as follows. Y Arithmetic Mean Standard Deviation 800 700 36 16
1) Complete the Distribution Table with the following data set of marital status: Single, Married, Single, Widowed, Married, Widowed, Engaged, Single, Widowed, Widowed, Married, Single, Widowed, Engaged, Widowed, Single, Single, Engaged, Married, Engaged, Widowed, Single, Married, Single, Engaged. Interval Single Engaged Married Widowed Frequency Relative Frequency Cumulative Frequency Cumulative Relative Frequency
Use frequency distribution table
Number of cases Number of cases Month produced (Columbus, produced (Tampa, Florida) Ohio) 1 684 819 1,080 836 3 720 888 773 897 5 1,016 903 831 907 7 835 912 8. 848 918 9 1,005 942 10 852 943 11 859 952 12 860 959 13 868 962 14 870 986 15 876 992 16 893 994 17 899 1,004 18 905 1,005 19 909 1,007 20 911 1,015 21 922 1,016 22 924 1,018 23 926 1,020 24 926 1,022 25 938 1,034 26 939 1,038 27 943 1,072 28 946 1,077 29 954 1,077 30 971 1,082 31 972 1,096 32 977 1,100 33 984 1,113 34 852 1,113 35 1,014 1,116 36 821 1,153 37 1,041 1,154 38 1,052 1,174 39 697 1,188 40 1,093 1,230
Isle Royale, an island in Lake Superior, has provided an important study site of wolves and their prey. Of special interest is the study of the number of moose killed by wolves. In the period from 1958 to 1974, there were 296 moose deaths identified as wolf kills. The age distribution of the kills is as follows. Age of Moose in Years Number Killed by Wolves Calf (0.5 yr)1-56-1011-1516-20 1115471573 μ = σ =
A standard million is often used for standardization. A standard millionrepresents the age distribution for a million citizens picked at randomfrom a population. Using the standard million reported in Table 1 as the external referencepopulation, directly adjust Arkansas’s crude deathrate.
Fill in the missing values for this ANOVA summary table round to two decimal places: S.S. d.f. М.S. Between 1114.872 2 Within ТОTAL 2968.872 20

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