(#4) I’m so confused, someone please help

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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(#4) I’m so confused, someone please help
### Find the Area

In the image, we are presented with a diamond-shaped quadrilateral (kite) which is divided into two congruent triangles by a diagonal. The dimensions provided in the diagram are:

- The lengths of the diagonals intersecting each other:
  - One diagonal measures 5 meters.
  - The other diagonal measures the sum of 3 meters and 3 meters, which is 6 meters.

#### Steps to Find the Area:
1. **Identify the diagonals:** 
   - Diagonal 1 (d₁): 5 meters
   - Diagonal 2 (d₂): 6 meters

2. **Apply the formula for the area of a kite:**
   The area (A) of a kite can be calculated using the formula:
   \[
   A = \frac{1}{2} \times d₁ \times d₂
   \]

3. **Plug in the values:**
   \[
   A = \frac{1}{2} \times 5 \, \text{m} \times 6 \, \text{m}
   \]

   \[
   A = \frac{1}{2} \times 30 \, \text{m}^2
   \]

   \[
   A = 15 \, \text{m}^2
   \]

#### Conclusion
The area of the kite is \( 15 \, \text{m}^2 \).
Transcribed Image Text:### Find the Area In the image, we are presented with a diamond-shaped quadrilateral (kite) which is divided into two congruent triangles by a diagonal. The dimensions provided in the diagram are: - The lengths of the diagonals intersecting each other: - One diagonal measures 5 meters. - The other diagonal measures the sum of 3 meters and 3 meters, which is 6 meters. #### Steps to Find the Area: 1. **Identify the diagonals:** - Diagonal 1 (d₁): 5 meters - Diagonal 2 (d₂): 6 meters 2. **Apply the formula for the area of a kite:** The area (A) of a kite can be calculated using the formula: \[ A = \frac{1}{2} \times d₁ \times d₂ \] 3. **Plug in the values:** \[ A = \frac{1}{2} \times 5 \, \text{m} \times 6 \, \text{m} \] \[ A = \frac{1}{2} \times 30 \, \text{m}^2 \] \[ A = 15 \, \text{m}^2 \] #### Conclusion The area of the kite is \( 15 \, \text{m}^2 \).
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