4) If F(x)= } d, then F'(x)- sin t

Q: What is A’(x) for this picture?

A: We need to find A'(x).

Q: If f(x) 3 find f'(2). x²

A: Given that f(x)=3x2So, f(x)=3x-2

Q: f(x) = (13 + 6t² + 1) dt

A: SOLUTION-

Q: 3) f(x) =9x/チxー3 %3D

A:

Q: Is the mathematical statement correct. If f(x)=f(-x), then f’(x)=f’(-x). Explain why

A:

Q: 2. Find f'(x): A. f(x)= 3x²+4 2x²-5

A:

Q: Suppose f(x) = 7x²+5x. Find: ƒ'(1) =

A: Given: f(x) = 7x2+5x

Q: 3 find f'(x). x2 7 If f(x) = 7+ -+

A:

Q: rsin(r2) Let g(x) 1 and f(x) g(t) dt. Find f' (2). xª + 1

A: From the given information we can apply the fundamental theorem of calculus.

Q: Give two function f(x) and f(x) such that the f''x is equal to -2.

A:

Q: If f '(3) = 0 and f"(3) < 0, then what must be true?

A: f '(3) = 0 and f"(3) &lt; 0

Q: {(u)= (u² -3)*

A: Given the function is  f(u) = 12u2-32. We have to find f'(u).

Q: If f(x) find f'(3) =

A: Given that: f(x)=4x2

Q: Find F '(x).

A:

Q: F:[- 2, 2]→ R, F(x) = (- 3Xf + 1) di

A: Given: Fx=∫-2x2t-3t2+1dt For finding derivative of given function, we will use fundamental theorem…

Q: Use the graph of f(x) to find the interval where f''(x) > 0. Ⓡ 3- 2- 1- ms -5 -4 -3 -2 -1 1 3 4 5 A.…

A: Here we have given the curve of f(x)  Now to determine all x value where  f"(x) &gt; 0

Q: If f(x) = 4, find f'(- 11).

A: The given function is:fx=4To find f'-11

Q: Let f(r) = 2e" + 7x + 6 , then f '(8) = Answer:

A: According to question given thatf(x)=2ex+7x+6

Q: B. f(x)=ln 5x² sin x (x+7)

A: We have to find the f'(x).

Q: Find f'(x).

A: The given function is,

Q: Let f(x)= = 4x² tan(x) sec(x) 1. f'(x)= 8x*sinx+4x^2*cosx 2. f'(1)= . Find the following:

A:

Q: Please help me with f(1), f'(1), f"(1) Thanks

A: To evaluate the derivatives (at 1) of the two given functions

Q: In x |find f"(e). If f(x)

A: