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4) I (2 A) – N = 60 turns N = 30 turns %3D •d Area (throughout) = 0.15 × 10-3 m² labcda = 0.16 m %3D Determine the secondary current for the transformer above if the resultant clockwise flux in the core is 1.5x10°Wb. (The material of the core depending on the last digit of your ID. If the last digit is between 1-4 use sheet steel. If it is between 5-8 use cast steel. If it is 0 or 9 use cast iron.).

4) I (2 A) – N = 60 turns N = 30 turns %3D •d Area (throughout) = 0.15 × 10-3 m² labcda = 0.16 m %3D Determine the secondary current for the transformer above if the resultant clockwise flux in the core is 1.5x10°Wb. (The material of the core depending on the last digit of your ID. If the last digit is between 1-4 use sheet steel. If it is between 5-8 use cast steel. If it is 0 or 9 use cast iron.).

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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4) I (2 A) – N = 60 turns N = 30 turns %3D •d Area (throughout) = 0.15 × 10-3 m² labcda = 0.16 m %3D Determine the secondary current for the transformer above if the resultant clockwise flux in the core is 1.5x10°Wb. (The material of the core depending on the last digit of your ID. If the last digit is between 1-4 use sheet steel. If it is between 5-8 use cast steel. If it is 0 or 9 use cast iron.).
Transcribed Image Text:4) I (2 A) – N = 60 turns N = 30 turns %3D •d Area (throughout) = 0.15 × 10-3 m² labcda = 0.16 m %3D Determine the secondary current for the transformer above if the resultant clockwise flux in the core is 1.5x10°Wb. (The material of the core depending on the last digit of your ID. If the last digit is between 1-4 use sheet steel. If it is between 5-8 use cast steel. If it is 0 or 9 use cast iron.).
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