4) Gaseous acetaldehyde CH₂CHO undergoes decomposition reaction where it was present at initial pressure P = 363 Torr. The rate of its decomposition v was 1.07 Torr s¹ when 5.0 % had reacted, and it was 0.76 Torr s¹ when 20.0 % had reacted. Determine the order of this reaction. Hint: start with generic formula v = k (P₂)". Then make a small Table with conversion rates, partial pressures, and reaction rates. Make the formula linear to the desired power a.

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4) Gaseous acetaldehyde CH₂CHO undergoes decomposition
reaction where it was present at initial pressure P. = 363 Torr.
The rate of its decomposition v was 1.07 Torr s¹ when 5.0 %
had reacted,
0
1
and it was 0.76 Torr s¹ when 20.0 % had reacted.
Determine the order of this reaction.
Hint: start with generic formula v = k (P)".
Then make a small Table with conversion rates, partial
pressures, and reaction rates. Make the formula linear to the
desired power a.
Transcribed Image Text:4) Gaseous acetaldehyde CH₂CHO undergoes decomposition reaction where it was present at initial pressure P. = 363 Torr. The rate of its decomposition v was 1.07 Torr s¹ when 5.0 % had reacted, 0 1 and it was 0.76 Torr s¹ when 20.0 % had reacted. Determine the order of this reaction. Hint: start with generic formula v = k (P)". Then make a small Table with conversion rates, partial pressures, and reaction rates. Make the formula linear to the desired power a.
Expert Solution
Step 1

According to the reaction,

The initial pressure of the gaseous acetaldehyde is given by = P0=363 torr

The rate of decomposition is given by,v=kPAα

where,

k = rate constantPA=Pressure at given timeα(alpha) = order of reaction

The two condition is also given,

v1 = 1.07 torr when 5.0% reactedv2= 0.76 torr when 20.0% reacted

 

Find- Order of reaction

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