4) Find Yp, using D-operator, where Yp (e). %3D (D+1) (D-2)

Q: (xCsc-)dナ×

A:

Q: x1 J: (x2+2x)2 dx= (x2+2x)3 C (x2 2x)3 C + 3 (x2+2x)3 +C 6 22-1C + -2 2x)1+C

A:

Q: Evaluate (x² + y²) dxdy

A:

Q: Find : (a) 4xSy³ + 2x?y-y-2x-4 0. %3D

A: Basic identities of differentiation is used along with the chain rule

Q: dx Vx² +9x² (In x³ )° 2

A:

Q: Evalvate 5x-12 X (x²+4) dx

A:

Q: (1) How much is 0! ? (by convention on). 0!

A: (1) Given

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A:

Q: X2 dx ex+3

A:

Q: Find + 3x*) dx 3 3 + C

A: Integral.

Q: Evaluate ((x-2)/x dx : 4 O 6 .6 テメ 11 3 11 * + C 11 6 4 + C 11 * テ x² +C /6

A:

Q: (3x/5y) (y2/6x)

A: The given expression is                                     3x5yy26x Now we simplify this given…

Q: sx2-9x-6 dx x3-2x2- 4xt8

A:

Q: V9 – 4x2 dx

A:

Q: (24+2x-x2)1/2dx

A:

Q: diffeventia! fox)=1ogn(9x) %3D %3D

A:

Q: Find 2dx x² + 8x + 17 Find dx xV5x2 – 3

A:

Q: Evaluate V1-x-dx A. --(x+xvI– x-) +C B. (x+xV1%3=x) +C c. (x+xv1+x-) +C D. -(x-xVT-x-) + C xv1-x)+ C

A: Find your answer below

Q: Evaluate 9x 9 (2x - 3)(x + 3) T -dx +C

A:

Q: Compute ď² dz² -(-x² − 3x² − x).

A: use differentiation of polynomial function.

Q: S dx 3 2 2X -4X-1) |

A:

Q: Find * L-1{ 52-4s+13

A:

Q: Differentiate y=(3x+1)2

A: Given,

Q: Evaluate: dx (A 2/ e* -+C 3x B 2Vx - (x- 1)e*-2+C O 2V-+C et e D

A:

Q: y = x² + x y = x + 5 2

A: y=x2+x y=x+5   a2-b2=(a-b)(a+b)